如何取消注释从 29 行到 39 行的行,如果存在某个文本?
文件内容 master.cf:
#
# Postfix master process configuration file. For details on the format
# of the file, see the master(5) manual page (command: "man 5 master" or
# on-line: http://www.postfix.org/master.5.html).
#
# Do not forget to execute "postfix reload" after editing this file.
#
# ==========================================================================
# service type private unpriv chroot wakeup maxproc command + args
# (yes) (yes) (no) (never) (100)
# ==========================================================================
smtp inet n - y - - smtpd
#smtp inet n - y - 1 postscreen
#smtpd pass - - y - - smtpd
#dnsblog unix - - y - 0 dnsblog
#tlsproxy unix - - y - 0 tlsproxy
#submission inet n - y - - smtpd
# -o syslog_name=postfix/submission
# -o smtpd_tls_security_level=encrypt
# -o smtpd_sasl_auth_enable=yes
# -o smtpd_tls_auth_only=yes
# -o smtpd_reject_unlisted_recipient=no
# -o smtpd_client_restrictions=$mua_client_restrictions
# -o smtpd_helo_restrictions=$mua_helo_restrictions
# -o smtpd_sender_restrictions=$mua_sender_restrictions
# -o smtpd_recipient_restrictions=
# -o smtpd_relay_restrictions=permit_sasl_authenticated,reject
# -o milter_macro_daemon_name=ORIGINATING
#smtps inet n - y - - smtpd
# -o syslog_name=postfix/smtps
# -o smtpd_tls_wrappermode=yes
# -o smtpd_sasl_auth_enable=yes
# -o smtpd_reject_unlisted_recipient=no
# -o smtpd_client_restrictions=$mua_client_restrictions
# -o smtpd_helo_restrictions=$mua_helo_restrictions
# -o smtpd_sender_restrictions=$mua_sender_restrictions
# -o smtpd_recipient_restrictions=
# -o smtpd_relay_restrictions=permit_sasl_authenticated,reject
# -o milter_macro_daemon_name=ORIGINATING
#628 inet n - y - - qmqpd
pickup unix n - y 60 1 pickup
cleanup unix n - y - 0 cleanup
已尝试以下命令:
sed -e '29,/smtpd_client_restrictions/s/^# //' master.cf
但它将解锁从 5 到 29 的 33 行
请说明如何执行此操作,smtpd_client_restrictions可以用其他文本替换。
谢谢!
编辑: 看到OP的评论看起来像OP可能需要取消注释,在这种情况下,仅取消注释第29行到第39行之间的匹配行,请尝试:
awk 'FNR>=29 && FNR<=39{if($0~/smtpd_client_restrictions/){sub(/^#/,"")}} 1' Input_file
您能否尝试以下操作。这将删除从第 29 行到 39 行的所有行中的注释,以防找到匹配的字符串。
awk '
FNR>=29 && FNR<=39{
if($0~/smtpd_client_restrictions/){
found=1
}
dup_val=(dup_val?dup_val ORS:"")$0
sub(/^#/,"")
val=(val?val ORS:"")$0
if(FNR==39 && found){
print val
val=""
}
else{
print dup_val
dup_val=""
}
next
}
1
' Input_file