我正试图找到一种方法来实现这一点——它试图计算一个短语在逐行文本文件中出现的次数

Question

每当我运行此代码时，它都会"告诉"我出现了一个错误，我需要做些什么才能让它告诉我团队出现在列表中的次数。给出的列表是WorldSeriesWinners。wins=0

try:
    input_file = open('WorldSeriesWinners.txt')
    team = input('Enter the team name: ')
    winner = input_file.readlines()
    for i in range(len(winner)):
        winner[i] = float(winner[i])
        if team in winner[i]:
            wins += 1
    print('The team ', team, ' won ', wins, ' World Series')
except IOError:
    print('The file could not be found.')
except IndexError:
    print('There was an indexing error.')
except:
    print('An error occurred.')

Answer 1

这里并没有真正回答您的问题，但我忍不住提出了一种更像蟒蛇的实现方式：

with open('WorldSeriesWinners.txt', 'r') as f:
    winners = [team.rstrip() for team in f.readlines()]
team = input('Enter the team name: ')
print(f'{team} won {winners.count(team)} world series')

一些快速解释：

• f.readlines()是所有行的列表(存储为字符串(。但是，其中包括换行符"\n"。方法.rstrip()去除字符串开头或结尾的空白，包括新行。

• [team.rstrip() for team in f.readlines()]就是我们所说的列表理解。

• count()方法计算潜在元素的出现次数；winners.count('New York Yankees')返回洋基队出现在名单中的次数。

• 字符串f'{team} won {winners.count(team)} world series'就是我们所说的f-string(在Python 3.6及以上版本中实现(。它是'{} won {} world series'.format(team, winners.count(team)的一个非常方便的等价物，所以请记住它。

Answer 2

所以。。。您不应该将获胜者的名字转换为float。此外，在用户传入单个字符的情况下，不应该使用in。这是更新后的代码：

wins = 0
input_file = open('WorldSeriesWinners.txt', 'r') # Specify to read file
team = input('Enter the team name: ')
winner = input_file.read().split("n") # Removes "n" on each line
for i in range(len(winner)):
    if winner[i] == team: # Check if inpout is equal instead of inside string
        wins += 1
print('The team', team, 'won', wins, 'World Series')

Answer 3

执行for winner in winners而不是for i in range(len(winner)):