JSON.Net序列化XML到JSON驼峰情况

Question

如何获取JSON。Net序列化我的XML骆驼的情况下JSON和没有"@"?

这是我目前拥有的，但它在属性前加上@，并且不驼驼大小写…

XmlDocument doc = new XmlDocument();
doc.LoadXml(myXmlString);
string jsonText = Newtonsoft.Json.JsonConvert.SerializeObject(doc, new JsonSerializerSettings()
{
    NullValueHandling = NullValueHandling.Ignore,
    ReferenceLoopHandling = ReferenceLoopHandling.Ignore,
    ContractResolver = new CamelCasePropertyNamesContractResolver()
});

Answer 1

创建XML数据模型

例子

public class MyClass
    {
        [JsonProperty("@SomeXMLProperty")]
        public string MyString{ get; set; }
    }

然后将XML反序列化到您的模型

XDocument xmlDocument = XDocument.Parse(xmlData);
string jsonData = JsonConvert.SerializeXNode(xmlDocument);
var myClass = JsonConvert.DeserializeObject<MyClass>(jsonData); 

然后只使用CamelCasePropertyNamesContractResolver和Formatting。缩进

string json = JsonConvert.SerializeObject(rootObject,
                              Newtonsoft.Json.Formatting.Indented,
                              new JsonSerializerSettings { ContractResolver = new Newtonsoft.Json.Serialization.CamelCasePropertyNamesContractResolver() });  

更新:

第一个解决方案简单明了(不需要编写自定义解析器等)，这只是为了删除@符号

  var xml = new XmlDocument();
  xml.XmlResolver = null;        
  xml.Load("yourfilehere");
  var json = JsonConvert.SerializeXmlNode(xml, Newtonsoft.Json.Formatting.Indented);
  var withoutATSign = System.Text.RegularExpressions.Regex.Replace(json, "(?<=")(@)(?!.*":\s )", String.Empty, System.Text.RegularExpressions.RegexOptions.IgnoreCase); 

如果有人知道这两种情况的更好的解决方案，那么第一个解决方案就很好了。

WebAPI添加

var json = GlobalConfiguration.Configuration.Formatters.JsonFormatter;
json.SerializerSettings.Formatting = Newtonsoft.Json.Formatting.Indented; 
json.SerializerSettings.ContractResolver = new CamelCasePropertyNamesContractResolver();