嵌套对象未保存JPA, Spring JPA Repository Oracle

Question

购物车和计划之间有一对多的关系。当我持久化购物车时，我想持久化购物车中的所有计划。我正在使用Spring JPA Repository。我尝试过单向和双向的联系。在每种情况下，它都会失败并产生以下错误:

org.springframework.dao。DataIntegrityViolationException: ORA-01400: cannot insert NULL into ("SS"."SS_CART_PLANS"."CART_ID");SQL (n/a);约束(空);嵌套异常是org.hibernate.exception.ConstraintViolationException: ORA-01400: cannot insert NULL into ("SS"."SS_CART_PLANS"."CART_ID")

映射如下:

@Entity
@Table(name = "SS_CART")
 public class Cart implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@SequenceGenerator(name="SS_CART_PLANS_ID_GENERATOR", sequenceName="SS_SEQ")
@GeneratedValue(strategy=GenerationType.SEQUENCE,                       generator="SS_CART_PLANS_ID_GENERATOR")
    private long id;
@OneToMany(cascade=CascadeType.ALL,mappedBy="cart")
private Set<CartPlan> cartPlans;
// uni-directional many-to-one association to SsUser
@ManyToOne(cascade= {CascadeType.ALL })
@JoinColumn(name = "USER_ID")
private User user;
public Cart() {
}
public long getId() {
    return this.id;
}
public void setId(long id) {
    this.id = id;
}
public Set<CartPlan> getCartPlans() {
    return this.cartPlans;
}
public void setCartPlans(Set<CartPlan> cartPlans) {
    this.cartPlans = cartPlans;
}
/**
 * @return the user
 */
public User getUser() {
    return user;
}
/**
 * @param user the user to set
 */
public void setUser(User user) {
    this.user = user;
}
}


    @Entity
@Table(name="SS_CART_PLANS")
public class CartPlan implements Serializable {
    private static final long serialVersionUID = 1L;
    @Id
    @SequenceGenerator(name="SS_CART_PLANS_ID_GENERATOR", sequenceName="SS_SEQ")
    @GeneratedValue(strategy=GenerationType.SEQUENCE, generator="SS_CART_PLANS_ID_GENERATOR")
    private long id;
    @Temporal(TemporalType.DATE)
    @Column(name="EFFECTIVE_DATE")
    private Date effectiveDate;
    @Column(name="ISSUER_CODE")
    private String issuerCode;
    @Column(name="PLAN_CODE")
    private String planCode;
    //bi-directional many-to-one association to SsCartPlan
    @OneToMany(cascade=CascadeType.ALL)
    @JoinColumn(name="PARENT_PLAN_ID")
    private Set<CartPlan> cartPlans;
    @ManyToOne
    @JoinColumn(name="CART_ID")
    @ForeignKey(name="SS_CART_PLANS_CART_FK")
    private Cart cart;
    //bi-directional one-to-one association to SsSearchCriteria
    @OneToOne(cascade=CascadeType.ALL)
    @JoinColumn(name="CRITERIA_ID")
    private SearchCriteria searchCriteria;
    public CartPlan() {
    }
    public long getId() {
        return this.id;
    }
    public void setId(long id) {
        this.id = id;
    }
    public Date getEffectiveDate() {
        return this.effectiveDate;
    }
    public void setEffectiveDate(Date effectiveDate) {
        this.effectiveDate = effectiveDate;
    }
    public String getIssuerCode() {
        return this.issuerCode;
    }
    public void setIssuerCode(String issuerCode) {
        this.issuerCode = issuerCode;
    }
    public String getPlanCode() {
        return this.planCode;
    }
    public void setPlanCode(String planCode) {
        this.planCode = planCode;
    }
    /**
     * @return the cartPlans
     */
    public Set<CartPlan> getCartPlans() {
        return cartPlans;
    }
    /**
     * @param cartPlans the cartPlans to set
     */
    public void setCartPlans(Set<CartPlan> cartPlans) {
        this.cartPlans = cartPlans;
    }
    /**
     * @return the searchCriteria
     */
    public SearchCriteria getSearchCriteria() {
        return searchCriteria;
    }
    /**
     * @param searchCriteria the searchCriteria to set
     */
    public void setSearchCriteria(SearchCriteria searchCriteria) {
        this.searchCriteria = searchCriteria;
    }
    /**
     * @return the cart
     */
    public Cart getCart() {
        return cart;
    }
    /**
     * @param cart the cart to set
     */
    public void setCart(Cart cart) {
        this.cart = cart;
    }
   }

Answer 1

我想你在粘贴CardPlan之前忘记设置card了