下面的代码使用 Spring 集成 2.2.6
我想通过回复通道将响应发送回入站网关。我正在发送来自服务激活器的回复。但是 Spring 无法设置响应,而是返回空消息
弹簧集成 xml 配置
<int-http:inbound-gateway id="entryHttpInboundGateway"
request-channel="entryInputChannel" path="/service/getSE/{uuid}" reply-channel="entryInboundReplyChannel"
request-payload-type="com.test.ServiceEvent" mapped-response-headers="eventUUID, HTTP_RESPONSE_HEADERS"
supported-methods="GET, POST" reply-timeout="1000" view-name="/process/plain2">
<int-http:header name="eventUUID" expression="#pathVariables.uuid"/>
</int-http:inbound-gateway>
<bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver" p:order="1"
p:defaultContentType="application/json">
<property name="defaultViews">
<list>
<bean class="org.springframework.web.servlet.view.json.MappingJacksonJsonView" />
</list>
</property>
</bean>
<int:service-activator id="sv2" input-channel="entryInputChannel" output-channel="outputChannel"
method="sendReply" requires-reply="true" ref="checkService">
</int:service-activator>
<bean id="checkService" class="com.test.CheckService" />
将消息发布到入站适配器回复通道(com.test.CheckService.java(
// Preparing the message to be sent to reply channel
InboundReplyResponse inboundReplyResponse = new InboundReplyResponse();
inboundReplyResponse.setMessage("Success");
inboundReplyResponse.setEventUUID("12345");
Map<String, Object> responseHeaderMap = new HashMap<String, Object>();
responseHeaderMap.put("eventUUID",eventUUID);
responseHeaderMap.put("Content-Type","application/json");
GenericMessage<InboundReplyResponse> message = new GenericMessage<InboundReplyResponse>(inboundReplyResponse,responseHeaderMap);
//Reply queue -> entryInboundReplyChannel
MessageChannel entryInboundReplyChannel = (MessageChannel) AppFactory.getApplicationContext().getBean("entryInboundReplyChannel");
entryInboundReplyChannel.send(message);
网络.xml
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-integration-context.xml</param-value>
</context-param>
<servlet>
<servlet-name>ssTesting</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>ssTesting</servlet-name>
<url-pattern>/service/*</url-pattern>
</servlet-mapping>
返回给客户端的响应
<Empty JSON content>
你的代码看起来很糟糕。
仅当您位于网关的调用线程中时,才能直接发送到该entryInboundReplyChannel
。因为网关的sendAndReceive
依赖于MessageHeaders
中的TemporaryReplyChannel
。最后一个是独立于inbound-gateway
上的明确reply-channel
而参与的。
为什么不使用entryInboundReplyChannel
作为<service-activator>
的output-channel
,而只是从sendReply
方法返回消息,而只是依靠 Framewrok 功能来正确调节流?
我不手动使用entryInboundReplyChannel.send(message)
。
已解决
// Instead of creating a new header, Request Message header should be used
public Message<ServiceMsg> (Message<?> inMessage){
....
....
GenericMessage<InboundReplyResponse> message = new GenericMessage<InboundReplyResponse>(inboundReplyResponse,inMessage.getHeaders());