我有一个我想从lib/a.js
和lib/b.js
创建的库lib.js
,并能够使用var a = require('lib/a.js');
从脚本client.js
使用它,并且当我只包括编译的lib.js
库时,它起作用了在client.js
之前(因此,lib.js
必须声明一个了解lib/a.js
的require
功能)
我想我必须使用external
和alias
,但我不确定正确的方法是什么
另外,是否有可能拥有一个湾文件,该文件会自动为我的库中的文件夹创建所有别名吗?例如。为lib/
DIR?
以下是几个Gulp任务,可以帮助您构建您的常见lib.js和client.js捆绑。
请注意,您必须告诉b.require()lib/*。js时,将b.rebquire()捆绑lib.js时,并且必须告诉b.external()b.external()库时将分别加载的库。JS
var path = require('path');
var gulp = require('gulp');
var browserify = require('browserify');
var concat = require('gulp-concat');
var transform = require('vinyl-transform');
gulp.task('build-lib', function () {
// use `vinyl-transform` to wrap around the regular ReadableStream returned by b.bundle();
// so that we can use it down a vinyl pipeline as a vinyl file object.
// `vinyl-transform` takes care of creating both streaming and buffered vinyl file objects.
var browserified = transform(function(filename) {
// basename, for eg: 'a.js'
var basename = path.basename(filename);
// define the exposed name that your client.js would use to require();
// for eg: require('lib/a.js'); // -> exposed name should be 'lib/a.js'
var expose = 'lib/' + basename;
return browserify(filename)
.require(filename, { expose: expose})
.bundle();
});
return gulp.src(['./lib/*.js'])
.pipe(browserified)
.pipe(concat('lib.js'))
.pipe(gulp.dest('./dist'));
});
gulp.task('build-client', function () {
var browserified = transform(function(filename) {
// filename = './client.js'
// let browserify know that lib/a.js and and lib/b.js are external files
// and will be loaded externally (in your case, by loading the bundled lib.js
// for eg: <script src='dist/lib.js'>)
return browserify(filename)
.external('lib/a.js')
.external('lib/b.js')
.bundle();
});
return gulp.src(['./client.js'])
.pipe(browserified)
.pipe(gulp.dest('./dist'));
});
gulp.task('default', ['build-lib', 'build-client']);
您是否正在寻找外部需求?
与Gulp-browserify一起使用,检查readme
.on('prebundle', function(bundle) {
bundle.external('domready');
bundle.external('react');
})
也应该与bundle.require一起工作。