为什么我的变量总是减少到零

Question

我正在写保龄球脚本。几个月前，我做了一个家庭作业，并在C 中工作，但现在我想在Bash中进行工作，因为我更喜欢它。

这是我的代码：

#!/bin/bash
for ((teamPlayer = 1 ; teamPlayer <= 5; teamPlayer++ )); do
        for ((bowlingGame = 1; bowlingGame <=3; bowlingGame++)); do
            read -p "Please enter the bowling score for Player number $teamPlayer in game number $bowlingGame: "
                    while [[ -z $REPLY  ]] || (( $REPLY > 300 ||  $REPLY < 1 )) || [[ ! $REPLY =~ [[:digit:]] ]]; do
                        if ((teamPlayer >=1 )); then 
                            (( bowlingScores +- REPLY ))
                            ((teamPlayer-1))
                            ((bowlingGame-1)) 
                        fi
                        echo -e "nError Try Again!"
                        read -p "Please enter the bowling score for Player number $teamPlayer in game number $bowlingGame: "
                    done
            (( bowlingScores += REPLY ))
    done
    (( bowlingScores += average ))
    echo "The average for player number $teamPlayer is $((average/3))" 
    (( average--))
done
echo "The average score for the team is $((bowlingScores/15))"

问题是当我尝试获得每个玩家的平均值时，平均值始终为零。我只想在显示平均值时降低平均值。另一个问题是，如果我不降低值，则每个玩家1之后的每个播放器的平均值错误。

任何帮助都将不胜感激。

编辑：使它起作用。这是新代码。

#!/bin/bash
for ((teamPlayer = 1 ; teamPlayer <= 5; teamPlayer++ )); do
        for ((bowlingGame = 1; bowlingGame <=3; bowlingGame++)); do
            read -p "Please enter the bowling score for Player number $teamPlayer in game number $bowlingGame: "

                    while [[ -z $REPLY  ]] || (( $REPLY > 300 ||  $REPLY < 1 )) || [[ ! $REPLY =~ [[:digit:]] ]]; do
                        if ((teamPlayer >=1 || bowlingGame >=1 )); then 
                            (( bowlingScores +- REPLY ))
                            ((teamPlayer >=1)) && ((teamPlayer-1))
                            ((bowlingGame-1)) && ((teamPlayer-1))
                        fi
                        echo -e "nError Try Again!"
                        read -p "Please enter the bowling score for Player number $teamPlayer in game number $bowlingGame: "
                    done
            (( bowlingScores += REPLY ))

            (( average += REPLY ))
    done

    echo "The average for player number $teamPlayer is $((average/3))" 
    average=0
done
echo "The average score for the team is $((bowlingScores/15))"
echo $bowlingScores

Answer 1

此部分：

(( bowlingScores +- REPLY ))
((teamPlayer-1))
((bowlingGame-1))

应该是：

(( bowlingScores += REPLY ))
((teamPlayer-=1))
((bowlingGame-=1))

检查：http：//tldp.org/ldp/abs/html/arithexp.html