如果存在两个桌子，则在Pythonic计数和刮擦以跳过第一张表

Question

我正在尝试从SEC文件中获取.xml数据。它在第二个桌子中。但是，如果我进入一个没有.xml的页面，我想要html vers，首先＆amp;只有表。如果有两个，请帮助我了解如何迭代或跳过第一张桌子，如果只有一个桌子在第一个桌子中获得第一个a ['href']？

from urllib2 import urlopen
import requests
from bs4 import BeautifulSoup
tableCount = 0
linklist = [https://www.sec.gov/Archives/edgar/data/1070789/000149315217011092/0001493152-17-011092-index.htm, https://www.sec.gov/Archives/edgar/data/1592603/000139160917000254/0001391609-17-000254-index.htm]
for l in linklist:
html = urlopen(l)
soup = BeautifulSoup(html.read().decode('latin-1', 'ignore'),"lxml")    
table = soup.findAll(class_='tableFile') # works for getting all .htm links
for item in table:
    tableCount +=1
url = table[0].a["href"]
if table.count >= 1:
    url = table[1].a["href"]
else:
    url = table.a["href"]

Answer 1

在两种情况下，您始终需要从最后一个表中的信息

import requests
from bs4 import BeautifulSoup
urls = ['https://www.sec.gov/Archives/edgar/data/1070789/000149315217011092/0001493152-17-011092-index.htm',
        'https://www.sec.gov/Archives/edgar/data/1592603/000139160917000254/0001391609-17-000254-index.htm']
for url in urls:
    response = requests.get(url)
    soup = BeautifulSoup(response.content, "html.parser")
    tables = soup.findAll('table', class_='tableFile')
    # assume xml table always comes after html one
    table = tables[-1]
    for a in table.findAll('a'):
        print(a['href'])  # you may filter out txt or xsd here