如何替换PowerShell脚本中程序集版本的第三个位置

Question

我有powershell脚本来替换程序集版本，但我必须在第三个位置更改版本号LIKE[assembly:AssemblyVersion（"1.0.20.1"）]到[汇编：汇编版本（"1.0.21.1"）]

这就是我所拥有的，它增加了最后一个位置：

#
# This script will increment the build number in an AssemblyInfo.cs file
#
$assemblyInfoPath = "C:UserskondasDesktopPowerShellAssemblyInfo.cs"
$contents = [System.IO.File]::ReadAllText($assemblyInfoPath)
$versionString = [RegEx]::Match($contents,"(AssemblyFileVersion("")(?:d+.d+.d+.d+)(""))")
Write-Host ("AssemblyFileVersion: " +$versionString)
#Parse out the current build number from the AssemblyFileVersion
$currentBuild = [RegEx]::Match($versionString,"(.)(d+)(""))").Groups[2]
Write-Host ("Current Build: " + $currentBuild.Value)
#Increment the build number
$newBuild= [int]$currentBuild.Value +  1
Write-Host ("New Build: " + $newBuild)
#update AssemblyFileVersion and AssemblyVersion, then write to file

Write-Host ("Setting version in assembly info file ")
$contents = [RegEx]::Replace($contents, "(AssemblyVersion(""d+.d+.d+.)(?:d+)(""))", ("`${1}" + $newBuild.ToString() + "`${2}"))
$contents = [RegEx]::Replace($contents, "(AssemblyFileVersion(""d+.d+.d+.)(?:d+)(""))", ("`${1}" + $newBuild.ToString() + "`${2}"))
[System.IO.File]::WriteAllText($assemblyInfoPath, $contents)

Answer 1

我会亲自用它制作一个对象，其中包含各个部分的值，然后您可以增加您想要的任何部分，然后将其重组为字符串。

$Version = $contents | ?{$_ -match 'AssemblyVersion("(d+).(d+).(d+).(d+)")'}|%{
    [PSCustomObject]@{
        [int]'First'=$Matches[1]
        [int]'Second'=$Matches[2]
        [int]'Third'=$Matches[3]
        [int]'Fourth'=$Matches[4]
    }
}

然后，您可以像$Version.Third++一样简单地增加第三个集合。然后只需使用格式化的字符串将其吐回：

'AssemblyVersion("{0}.{1}.{2}.{3}")' -f $Version.First, $Version.Second, $Version.Third, $Version.Fourth

这将产生你想要的AssemblyVersion("1.0.21.1")。