XSLT:使用一个键交叉引用第二个键

Question

我需要将XML转换为格式为以下格式的表网格：

A1,B1,C1
A2,B2,C2
A3,B3,C3

我正在使用的 XML 为每条记录提供一个单元格值，但每条记录提供一个星期几(列(和流(行(值。

我使用两个键进行了简单的 XSLT 转换，一个用于流，一个用于一周之日。这些工作很成功，因为我有 3 行，每个流一行，以及 3 列，一周中的每一天一列。但是，内容只是重复的第一行(即

A1,B1,C1,
A1,B1,C1,
A1,B1,C1

如何根据这两个关键条件在表格单元格中选择 DisplayStuff？

这是我的 XSLT：

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes" encoding="us-ascii" />
<xsl:key name="DayOfWeek1" match="DataRow" use="DayOfWeek" />
<xsl:key name="Stream1" match="DataRow" use="Stream" />
<xsl:template match="QueryResults">
<table>
<xsl:for-each select="//DataRow[generate-id() = generate-id(key('Stream1',Stream)[1])]">
<tr style="border: 1px solid black;" class="scrolling">
<xsl:for-each select="//DataRow[generate-id() = generate-id(key('DayOfWeek1',DayOfWeek)[1])]">

<td style="border: 1px solid black;" width="100px">
<xsl:value-of select="DisplayStuff" />
</td>
</xsl:for-each>
</tr>
</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>

.XML：

<?xml version="1.0" encoding="UTF-8"?>
<QueryResults>
<DataRow>
<Stream>1</Stream>
<DayOfWeek>1</DayOfWeek>
<DisplayStuff>A1</DisplayStuff>
</DataRow>
<DataRow>
<Stream>1</Stream>
<DayOfWeek>2</DayOfWeek>
<DisplayStuff>B1</DisplayStuff>
</DataRow>
<DataRow>
<Stream>1</Stream>
<DayOfWeek>3</DayOfWeek>
<DisplayStuff>C1</DisplayStuff>
</DataRow>
<DataRow>
<Stream>2</Stream>
<DayOfWeek>1</DayOfWeek>
<DisplayStuff>A2</DisplayStuff>
</DataRow>
<DataRow>
<Stream>2</Stream>
<DayOfWeek>2</DayOfWeek>
<DisplayStuff>B2</DisplayStuff>
</DataRow>
<DataRow>
<Stream>2</Stream>
<DayOfWeek>3</DayOfWeek>
<DisplayStuff>C2</DisplayStuff>
</DataRow>
<DataRow>
<Stream>3</Stream>
<DayOfWeek>1</DayOfWeek>
<DisplayStuff>A3</DisplayStuff>
</DataRow>
<DataRow>
<Stream>3</Stream>
<DayOfWeek>2</DayOfWeek>
<DisplayStuff>B3</DisplayStuff>
</DataRow>
<DataRow>
<Stream>3</Stream>
<DayOfWeek>3</DayOfWeek>
<DisplayStuff>C3</DisplayStuff>
</DataRow>
</QueryResults>

Answer 1

试试这样吗？

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="row-by-day" match="DataRow" use="DayOfWeek" />
<xsl:key name="row-by-stream" match="DataRow" use="Stream" />
<xsl:template match="/QueryResults">
<!-- a column for each distinct day of week  -->
<xsl:variable name="columns" select="DataRow[generate-id() = generate-id(key('row-by-day', DayOfWeek)[1])]" />
<table border="1">
<!--  a row for each distinct stream -->
<xsl:for-each select="DataRow[generate-id() = generate-id(key('row-by-stream', Stream)[1])]">
<xsl:variable name="stream" select="key('row-by-stream', Stream)" />
<tr>
<!-- a cell for each column -->
<xsl:for-each select="$columns">
<xsl:sort select="DayOfWeek" data-type="number" order="ascending"/>
<td>
<xsl:value-of select="$stream[DayOfWeek = current()/DayOfWeek]/DisplayStuff" />
</td>
</xsl:for-each>
</tr>
</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>

---

请注意，这假设Stream和DayOfWeek的每个交集最多有一个DataRow。