我目前正在尝试制作我的项目,以便当选择一个无线电按钮并保留一个按钮时,它会产生所选的声音。但是,当我使用Action_Down函数时,不会产生噪声。任何帮助都很棒
public boolean onTouch(View v, MotionEvent event) {
int frequency = Integer.parseInt(frequencyInput.getText().toString());
displayFrequency.setText(String.valueOf(frequency));
sineWave.setSine(frequency);
squareWave.setSquareWave(frequency);
sawWave.setSawWave(frequency);
boolean on = ((startStop.isPressed()) && sine.isChecked());
boolean sqOn = ((startStop.isPressed()) && square.isChecked());
boolean sawOn =((startStop.isPressed()) && saw.isChecked());
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
if (on)
{
sineWave.start();
}
else if (sqOn)
{
squareWave.start();
}
else if (sawOn)
{
sawWave.start();
}
break;
case MotionEvent.ACTION_UP:
if (!on) {
sineWave.stop();
}
if (!sqOn) {
squareWave.stop();
}
if (!sawOn) {
sawWave.stop();
;
}
break;
}
主要问题是您仍在onTouch
时检查isPressed()
,因此尚未设置按钮的按下状态。
如果将onTouchListener
直接添加到StartSpop按钮中,则可以确定每次称为它是触发事件的StartSpop按钮。这使您可以删除startStop.isPressed()
检查。
startStop.setOnTouchListener(new View.OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
int frequency = Integer.parseInt(frequencyInput.getText().toString());
displayFrequency.setText(String.valueOf(frequency));
sineWave.setSine(frequency);
squareWave.setSquareWave(frequency);
sawWave.setSawWave(frequency);
boolean on = sine.isChecked();
boolean sqOn = square.isChecked();
boolean sawOn = saw.isChecked();
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
if (on) {
sineWave.start();
} else if (sqOn) {
squareWave.start();
} else if (sawOn) {
sawWave.start();
}
break;
case MotionEvent.ACTION_UP:
if (!on) {
sineWave.stop();
}
if (!sqOn) {
squareWave.stop();
}
if (!sawOn) {
sawWave.stop();
}
break;
default:
return false;
}
return true;
}
});