我正在尝试在一次加载中加载多个文件。它们都是分区文件当我尝试使用 1 个文件时它可以工作,但是当我列出 24 个文件时,它给了我此错误,除了在加载后进行联合之外,我找不到任何限制和解决方法的文档。还有其他选择吗?
下面的代码以重现问题:
basepath = '/file/'
paths = ['/file/df201601.orc', '/file/df201602.orc', '/file/df201603.orc',
'/file/df201604.orc', '/file/df201605.orc', '/file/df201606.orc',
'/file/df201604.orc', '/file/df201605.orc', '/file/df201606.orc',
'/file/df201604.orc', '/file/df201605.orc', '/file/df201606.orc',
'/file/df201604.orc', '/file/df201605.orc', '/file/df201606.orc',
'/file/df201604.orc', '/file/df201605.orc', '/file/df201606.orc',
'/file/df201604.orc', '/file/df201605.orc', '/file/df201606.orc',
'/file/df201604.orc', '/file/df201605.orc', '/file/df201606.orc', ]
df = sqlContext.read.format('orc')
options(header='true',inferschema='true',basePath=basePath)
.load(*paths)
收到的错误:
TypeError Traceback (most recent call last)
<ipython-input-43-7fb8fade5e19> in <module>()
---> 37 df = sqlContext.read.format('orc') .options(header='true', inferschema='true',basePath=basePath) .load(*paths)
38
TypeError: load() takes at most 4 arguments (24 given)
如官方文档中所述,要读取多个文件,您应该传递一个list
:
path – 文件系统支持的数据源的可选字符串或字符串列表。
所以在你的情况下:
(sqlContext.read
.format('orc')
.options(basePath=basePath)
.load(path=paths))
参数解包(*
(只有在用可变参数定义时才有意义load
,例如:
def load(this, *paths):
...