比较字符串循环蟒蛇

Question

我正在尝试创建一个循环来比较我已经创建的列表中的字符串。该列表是密码，以及使用 md5 散列的相同密码。我有一个进行哈希处理的函数，另一个函数可以打印出两个密码的列表。新函数"findmd5"应该将密码列表的每个md5加密值与传入的加密字符串进行比较。"pass2check"是我尝试在循环中使用的预定字符串，其 md5 值应返回密码"足球"。我的新函数中的代码非常不完整，因为我迷失了接下来要采取的步骤。

import hashlib
passwordlist = ["password","123456","12345678","1234","qwerty","12345",
"baseball","football","letmein","monkey","abc123","mustang","michael"]
def makemd5(key_string):
    new_key_string = key_string.encode('utf-8')
    return (hashlib.md5 ( new_key_string ).hexdigest())
def createmd5list(passwordlist):
    for passlist in passwordlist:
        hashlist = makemd5(passlist)
        print (passlist,",",hashlist)
def findmd5(pass2check):
    for line in open(passwordlist + hashlist): 
        if pass2check in line:
            print(True)
        else:
            print(False)

def main():
    pass2check = "37b4e2d82900d5e94b8da524fbeb33c0"

main ()

Answer 1

你可以试试这个((：

import hashlib
passwordlist = ["password","123456","12345678","1234","qwerty","12345",
"baseball","football","letmein","monkey","abc123","mustang","michael"]
def listOfHashs():
    return [hashlib.md5(item.encode('utf-8')).hexdigest() for item in passwordlist]
def main():
    pass2check = "37b4e2d82900d5e94b8da524fbeb33c0"
    index = listOfHashs().index(pass2check)
    print(passwordlist[index] if index >= 0 else "Hash not found !")
main()

在这个版本中，我尝试修改您的代码：

import hashlib
passwordlist = ["password","123456","12345678","1234","qwerty","12345",
"baseball","football","letmein","monkey","abc123","mustang","michael"]
def makemd5(key_string):
    new_key_string = key_string.encode('utf-8')
    return (hashlib.md5 ( new_key_string ).hexdigest())
def createmd5list(passwordlist):
    hashlist = []
    for passlist in passwordlist:
        hashlist += [makemd5(passlist)]
    return hashlist
def findmd5(pass2check):
    for index, line in enumerate(createmd5list(passwordlist)): 
        if pass2check in line:
            return index
    return -1

def main():
    pass2check = "37b4e2d82900d5e94b8da524fbeb33c0"
    index = findmd5(pass2check)
    if index >= 0:
        print passwordlist[index]
    else:
        print "Hash not found !"
main()

Answer 2

您不需要创建散列密码列表。相反，您可以在列表推导式中构建摘要和筛选器，最终列表仅包含有效的解决方案。

重新设计您自己的代码，它可能看起来像

import hashlib
passwordlist = ["password","123456","12345678","1234","qwerty","12345",
    "baseball","football","letmein","monkey","abc123","mustang","michael"]
def findmd5(pass2check):
    result = [password for password in passwordlist 
              if hashlib.md5(password).hexdigest() == pass2check
             ]
    if len(result):
        print("The answer is")
        for password in result:
            print(password)
    else:
        print("Password not found")
def main():
    pass2check = "37b4e2d82900d5e94b8da524fbeb33c0"
    findmd5(pass2check)

main ()

这将打印所有有效的解决方案