graphql中未定义类型的输出错误

Question

我用mongodb在graphql-server和nodejs中编写了一个简单的代码。我有一个数据库，里面有两个集合。明星和电影。当我运行这个查询来显示所有电影时，我的GraphQL NodeJS服务器出现以下错误："MovieType.year的类型必须是Output type，但get:undefined。">

这是我的模式：

const {
GraphQLSchema,
GraphQLObjectType,
GraphQLString,
GraphQLInt,
GraphQLNonNull,
GraphQLList
} = require("graphql");
const {Movie, User} = require('/home/fateme/imdb_final/db')

const starType = new GraphQLObjectType({
name: "UserType",
fields: {
name: {
type: GraphQLString,
async resolve(objId) {
const starFind = await User.findOne({ _id: objId._id})
return starFind.name
}
},
imdbId: {
type: GraphQLString,
async resolve(objId) {
const starFind = await User.findOne({ _id: objId._id}) 
return starFind.imdbId
}
}
}
});
const movieType = new GraphQLObjectType({
name: "MovieType",
fields: {
title: {
type: GraphQLString,
async resolve(objId) {
const movieFind = await Movie.findOne({ _id: objId._id})
return movieFind.title
}
},
year: {
type: GraphQLInt,
async resolve(objId) {
const movieFind = await Movie.findOne({ _id: objId._id})
return movieFind.year
}
},
rate: {
type: GraphQLInt,
async resolve(objId) {
const movieFind = await Movie.findOne({ _id: objId._id})
return movieFind.rating
}
},
year: {
rate: GraphQLInt,
async resolve(objId) {
const movieFind = await Movie.findOne({ _id: objId._id})
return movieFind.year
}
},
director: {
type: GraphQLString,
async resolve(objId) {
const movieFind = await Movie.findOne({ _id: objId._id})
return movieFind.director
}
},
}
});

const queryType = new GraphQLObjectType({
name: 'Query',
fields: () => ({
users: {
type: GraphQLList(starType),
async resolve() {
const allStar = await User.find({})
return  allStar
}
},
movies: {
type: GraphQLList(movieType),
async resolve() {
const allMovie = await Movie.find({})
console.log(allMovie)
return  allMovie
} 
},
})
});
const schema = new GraphQLSchema({
query: queryType
});
module.exports = schema;

Answer 1

如错误所示，您尚未为year字段定义类型。相反，您意外地添加了一个rate字段：

year: {
rate: GraphQLInt, // <-- here
async resolve(objId) {
const movieFind = await Movie.findOne({ _id: objId._id})
return movieFind.year
}
},

只需将rate更改为type，就可以使用：(