在C 程序上工作。想要制作一个用户名"检查器"。在一段时间内处理ifstream。我遇到的问题是,如果不存在用户名,那么它每次都在文本中打印错误消息。我知道问题是在循环中。我不知道如何在不检查用户名的文件的情况下提供错误消息。任何帮助将不胜感激。谢谢!
string username;
string password;
int input;
bool keepGoing;
while (keepGoing){
cout<<("1.Loginn2.Create Username and Passwordn3.Exit")<<endl;
cin>>input;
///////////////////////////////////////////////////////////
if(input == 1){ //LOGIN!!!
//open the file
ifstream user("userinfo.txt");
if(user.is_open()){
//get the username
string checkUser;
string checkPass;
cout<<"Enter username: "<<endl;
cin>>checkUser;
//create a variable to store existing username
//Iterate throught the text file, and log them in if thier info is correct
//while(user>>username>>password){
while(getline(user, username)){
//if the name is there
if (checkUser != username){
cout<<"Username not here!"<<endl;
}
if (checkUser==username){
//cout<<"Welcome back, "<<username<<endl;
cout<<"Password: "<<endl;
cin>>checkPass;//get user input
if(checkPass==password){//if the password is correct
cout<<"Welcome back, "<<username<<endl;//User is logged in
//put in the menu 2 function
}else if(checkPass!=password){//If pass is incorrect
cout<<"Password incorrect."<<endl;//Denied
}//end else if
}//end if
}//end while loop
}
else{
cout<<"Unable to open file"<<endl;
}
}
只是这样做
bool foundUser = false;
while(getline(user, username)) {
if(checkUser == username) {
foundUser = true;
break;
}
}
if(foundUser) {
// check password here
}
else {
// display error message
}
您应该将检查用户名的逻辑提取到一个函数中,该函数将在sucsses上返回true,false在失败上。
bool checkUser(const std::string& username, const std::string& pass){
//check if user exists
while(getline()){
if(username == somthing)
{
if(pass == somthing){
return true;
}
std::cout << "incorrect pass";
return false;
}
}
//if you reached here than the username doesnt exists
return false;
}