我在Raspberry Pi上有一个简单的脚本,它每3秒发布一条示例消息。我已经声明了回调on_connect、on_publish和on_pdisconnect。此客户端连接成功,但未调用on_connect,调用publish和on_publish,断开连接并调用on_pdisconnect。
这是我的脚本
import paho.mqtt.client as mqtt
import time
def on_connect(mqttc, userdata, rc):
print("Connected with result code "+str(rc))
if rc!=0 :
mqttc.reconnect()
def on_publish(mqttc, userdata, mid):
print "Published"
def on_disconnect(mqttc, userdata, rc):
if rc != 0:
print("Unexpected disconnection. Reconnecting...")
mqttc.reconnect()
else :
print "Disconnected successfully"
# Setup MQTT
# broker='test.mosquitto.org'
broker = 'iot.eclipse.org'
broker_port=1883
# Create a client instance
mqttc=mqtt.Client(client_id="MyClient")
mqttc.on_connect = on_connect
mqttc.on_publish = on_publish
mqttc.on_disconnect = on_disconnect
while 1:
mqttc.connect(broker, broker_port, 60)
# print "Connected." # I don't want this message.
# Why isn't the on_connect callback invoked?
try:
topic = "this/is/a/test/topic"
payload = "test_message"
print "Publishing " + payload + " to topic: " + topic + " ..."
mqttc.publish(topic, payload, 0)
except Exception as e:
print "exception"
log_file=open("log.txt","w")
log_file.write(str(time.time())+" "+e.__str__())
log_file.close()
mqttc.disconnect()
print ""
time.sleep(3)
虽然这个小"错误"不会影响消息发布,这主要是我想要实现的,但为什么会发生这种情况,我该如何解决?
这不起作用的原因是您没有调用任何loop*()
函数。这些处理网络流量。如果你不使用它,就不能保证你的传出消息会被发送,也绝对不会处理传入消息。
loop_forever()
是一个处理网络环路的阻塞调用,可能不是您想要的。
loop_start()
启动一个线程来处理网络循环,因此立即返回。
我会这样做:
mqttc.connect(broker, broker_port, 60) # Don't forget to handle errors
mqttc.loop_start()
while 1:
try:
topic = "this/is/a/test/topic"
payload = "test_message"
print "Publishing " + payload + " to topic: " + topic + " ..."
mqttc.publish(topic, payload, 0)
except Exception as e:
print "exception"
log_file=open("log.txt","w")
log_file.write(str(time.time())+" "+e.__str__())
log_file.close()
print ""
time.sleep(3)
正如@Kiran所说,你仍然需要修复你的on_connect回调。
没有必要每次都断开连接——事实上,也不能保证当你断开连接时,你的信息会被发送出去。您应该使用on_publish
回调来了解消息的发送时间。
如果你想做一个简单的连接-发布-断开连接,那么可以使用paho.mqtt.publish
辅助模块:
import paho.mqtt.publish as publish
while 1:
try:
topic = "this/is/a/test/topic"
payload = "test_message"
print "Publishing " + payload + " to topic: " + topic + " ..."
publish.single(topic, payload, 0, host=broker, port=broker_port)
except Exception as e:
print "exception"
log_file=open("log.txt","w")
log_file.write(str(time.time())+" "+e.__str__())
log_file.close()
print ""
time.sleep(3)
您的on_connect()
方法声明缺少标志(1)参数。因此,它没有被调用。Flags参数包含broker发送的响应。必须是
def on_connect(mqttc, userdata, flags, rc):
另外,为什么要在回路中连接和断开?尝试使用loop_start()
和loop_stop()
方法来处理断开连接时的自动重新连接(示例)。