PostgreSQL:如何按时间表间隔30分钟来选择员工和组的时间范围



我有三列,即时间段(时间戳),超时(时间戳)和员工。我需要获取在特定时间范围内工作的员工人数(间隔30分钟)。例如:

    employee_id              timein              timeout
    101                      10:10               12:59
    102                       9:07               12:16
    103                      11:16               12:08

我需要一个可以给我这个结果的查询

    timeframe         count(employee_id)
    09:00                    1
    09:30                    1
    10:00                    2
    10:30                    2
    11:00                    3
    11:30                    3
    12:00                    3
    12:30                    1

我真的希望我能清楚地表明。谢谢

请参阅此演示:http://sqlfiddle.com/#!17/2477f/1

SELECT x.timeframe, count(employee_id)
FROM (
   select time '8:00' + x * interval '30 minute' as timeframe,
          time '8:00' + (x+1) * interval '30 minute' as timeframe_end
   from generate_series(0,10) x
) x
LEFT JOIN employee t
/* (StartA <= EndB) and (EndA >= StartB) */
ON x.timeframe <= t.timeout
AND x.timeframe_end >= t.timein
GROUP BY x.timeframe
ORDER BY 1
SELECT x.timeframe, count(employee_id)
FROM (
   select time '8:00' + x * interval '30 minute' as timeframe,
          time '8:00' + (x+1) * interval '30 minute' as timeframe_end
   from generate_series(0,12) x
) x
LEFT JOIN employee t
/* (StartA < EndB) and (EndA > StartB) */
ON x.timeframe < t.timeout
AND x.timeframe_end > t.timein
GROUP BY x.timeframe
ORDER BY 1
| timeframe | count |
|-----------|-------|
|  08:00:00 |     0 |
|  08:30:00 |     0 |
|  09:00:00 |     1 |
|  09:30:00 |     1 |
|  10:00:00 |     2 |
|  10:30:00 |     2 |
|  11:00:00 |     3 |
|  11:30:00 |     3 |
|  12:00:00 |     3 |
|  12:30:00 |     1 |
|  13:00:00 |     1 |
|  13:30:00 |     1 |
|  14:00:00 |     0 |

联接条件使用此答案中的公式来检查两个范围是否重叠:

(starta&lt; endb)和(enda> startb)

演示还显示了查询对边缘情况的行为:

(113, '13:00', '13:01'),
(115, '13:30', '14:00')

后者的雇员从13:30开始,并于14:00完成,因此它包含在13:30时限中,中,但不包括在14:00 TimeFrame中。

|  13:00:00 |     1 |
|  13:30:00 |     1 |
|  14:00:00 |     0 |

问题可能是在同一时间范围内多次开始和完成工作的雇员(例如,频繁咖啡休息的工人),例如:

(113, '13:00', '13:01'),
(113, '13:12', '13:15'),
(113, '13:22', '13:26')

在这种情况下,您需要计算不同的员工,使用:count(DISTINCT employee_id)

尝试这样的东西。

SELECT timeframe,
COUNT (employee_id)
FROM employee a
RIGHT JOIN
(SELECT *
 FROM generate_series (TIMESTAMP '2017-09-01 09:00:00', 
                       TIMESTAMP '2017-09-01 17:00:00', 
               INTERVAL '0.5 HOUR' ) AS timeframe) b 
                 ON b.timeframe >=  timein
                 AND b.timeframe <= timeout
GROUP BY timeframe
ORDER BY timeframe ;
SELECT out_time-in_time time_frame, count(*) FROM
TABLE_NAME GROUP BY out_time-in_time

我针对示例本地数据进行了测试。

employee_id | in_time  | out_time 
-------------+----------+----------
         101 | 09:07:00 | 12:08:00
         102 | 10:07:00 | 17:08:00
         103 | 12:07:00 | 17:08:00
         104 | 12:07:00 | 17:08:00
         105 | 10:07:00 | 17:08:00

从查询输出。

time_frame | count 
------------+-------
 07:01:00   |     2
 03:01:00   |     1
 05:01:00   |     2

您可以在找到差异时相应地包括逻辑。

sql小提琴

PostgreSQL 9.6架构设置

CREATE TABLE emp_time
    ("employee_id" int, "timein" time, "timeout" time)
;
INSERT INTO emp_time
    ("employee_id", "timein", "timeout")
VALUES
    (101, '10:10', '12:59'),
    (102, '9:07', '12:16'),
    (103, '11:16', '12:08')
;

查询1

SELECT 
      slot_start
    , slot_end
    , count(employee_id)
FROM  (
      SELECT slot_start, slot_start + INTERVAL '30 MINUTE' slot_end
      FROM generate_series (TIMESTAMP '2017-01-01 09:00:00', TIMESTAMP '2017-01-01 16:30:00', INTERVAL '30 MINUTE' ) AS slot_start
      ) t 
LEFT JOIN emp_time et ON et.timein < t.slot_end::time and et.timeout > t.slot_start::time
GROUP BY
      slot_start
    , slot_end
ORDER BY
      slot_start
    , slot_end
;

结果

|           slot_start |             slot_end | count |
|----------------------|----------------------|-------|
| 2017-01-01T09:00:00Z | 2017-01-01T09:30:00Z |     1 |
| 2017-01-01T09:30:00Z | 2017-01-01T10:00:00Z |     1 |
| 2017-01-01T10:00:00Z | 2017-01-01T10:30:00Z |     2 |
| 2017-01-01T10:30:00Z | 2017-01-01T11:00:00Z |     2 |
| 2017-01-01T11:00:00Z | 2017-01-01T11:30:00Z |     3 |
| 2017-01-01T11:30:00Z | 2017-01-01T12:00:00Z |     3 |
| 2017-01-01T12:00:00Z | 2017-01-01T12:30:00Z |     3 |
| 2017-01-01T12:30:00Z | 2017-01-01T13:00:00Z |     1 |
| 2017-01-01T13:00:00Z | 2017-01-01T13:30:00Z |     0 |
| 2017-01-01T13:30:00Z | 2017-01-01T14:00:00Z |     0 |
| 2017-01-01T14:00:00Z | 2017-01-01T14:30:00Z |     0 |
| 2017-01-01T14:30:00Z | 2017-01-01T15:00:00Z |     0 |
| 2017-01-01T15:00:00Z | 2017-01-01T15:30:00Z |     0 |
| 2017-01-01T15:30:00Z | 2017-01-01T16:00:00Z |     0 |
| 2017-01-01T16:00:00Z | 2017-01-01T16:30:00Z |     0 |
| 2017-01-01T16:30:00Z | 2017-01-01T17:00:00Z |     0 |

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