在他离开"enter"选项后，我如何保留用户输入的值并让他从完成开始？

Question

我必须做一定的练习。希望有人了解我未能做的事情。

每当用户按ENTER时，以少于10个整数输入时，按Q退出选项，然后返回，他的所有输入值都将消失。我想输入值留在那里，直到存储的总元素为10。我该怎么做？

注意！用户不应该退出应用程序（在这种情况下为CMD），而应该只能留下" Enter"选项并仍然具有"存储"的输入值。

#include <math.h>
#include <string.h>
#include <stdio.h>
#include <stdlib.h>
#define L 10
void view(int a[])
     {
        int i;
        printf("n Here are the currently stored valuesn");  
        printf("[");
        for(i=0; i<L; i++)
            {
            printf(" %d ",a[i]);
            }
        printf("]");
     }
int enter(int a[], int n)
     {
         printf("n Note! You can press any letter if you want to return to the main menu. n");
         for(int i=0; i<L; i++)
            {
            int mesa;
            printf(" Enter measurement #%d (or q to quit): ", n+1);
            int check = scanf("%d",&mesa); 
            if(check)
                {
                    a[i] = mesa;
                    n++;
                }
            else
                { 
                    char temp;
                    scanf(" %c",&temp);
                    return n;
                }
            }
           return n;
     }
void compute(int a[], int n)
     {
            printf(" Computing...n");
            //Min value
            {
                int i;
                int min = 10000;
                for (i = 0; i < L; i++)
                if(a[i] < min)
                min = a[i];
                printf("n The min value is: %d n", min);
            }
            //Max value
            {
                int i;
                int max = a[0];
                for (i = 0; i < L; i++) 
                if (a[i] > max) 
                max = a[i]; 
               printf(" The max value is: %d n", max);
            }
            // Average & Normalization
            {
                float average;
                int i;
                int norm;
                int sum;
                for(i = 0; i < L; ++i)
                    {
                    sum = sum + a[i];
                    average = (float)sum / 10; //typecast - Ge en interger en tillfällig roll. På så sätt kan du säga åt programmet att du faktiskt vill ha float som svar och inte ett heltal som svar.
                    } 
                    printf(" Average value: %.2f n", average);
                    printf(" Normalized array: [");
                for(i = 0; i < L; i++)
                    {
                    norm = a[i] - average; //average - every a[]
                    printf(" %d", (int)round(norm));
                    }
                    printf(" ]");
            }
     }
void reset(int a[])
    {
        printf(" You have chosen to reset the array. All the elements in the array will now be deleted. n");
        //memset( a, 0, 10*sizeof(a)); <--- Kan ej användas då sizeof() funktionen läser av en variabel och inte hela arrayens storlek.
        memset( a, 0, 10*sizeof(int*));
    }
int main()
{
    char command;
    int a[L];
    printf(" Hello and welcome to this measurement tool. In this program you will be able to type in and analyze data.n");
    printf(" In the section below, you can choose a letter v,e,c,r or q to do certain things. More information will be provided down below.n");
    printf("n v(View) - Displays currently stored values.");
    printf("n e(Enter) - Allows you to store values. ");
    printf("n c(Compute) - Displays the maxiumum, minimum, normalized and average value of those which are stored.");
    printf("n r(Reset) - Deletes all stored values.");
    printf("n q(Quit) - Exits the program. n");
    printf("n Please choose one of the commands above: ");
    do
    {
      int n = 0;
      scanf(" %c",&command);
      switch(command)
       {
            case 'v' : view(a);break;
            case 'e' : enter(a,n);break;
            case 'c' : compute(a,n);break;
            case 'r' : reset(a);break;
            default : printf("n Please choose one of the options given.n");break;
            case 'q' : 
                    {
                    printf(" Want to exit? Confirmation needed. Press q again to exit.");
                    scanf(" %c",&command);
                    }   
        }
            printf("n VECRQ?: ");
    } while(command != 'q');
return 0;
}

Answer 1

在main()中，将n的声明移到循环外：

int n = 0;
do
{
    ...

更新n时，您致电enter()：

n = enter(a,n);

在enter功能中，从n启动循环：

for(int i=n; i<L; i++)