我正在编写一个在 Swift 3/Xcode 8 中包含 Alamofire 网络请求的方法。当包装在标准函数中时,以下代码块编译时没有错误:
func registerUser(firstName: String, lastName: String, email: String, username: String, password: String, profilePicture: String, completion: @escaping(JSON?) -> ()) {
let params: [String:Any]? = [
"first_name" : firstName,
"last_name" : lastName,
"email" : email,
"username" : username,
"password" : password,
"profile_pic" : profilePicture
]
Alamofire.request("(baseURL)/users/create", method: .post, parameters: params, encoding: JSONEncoding.default, headers: nil).responseJSON { response in
switch response .result {
case .success(let value) :
completion(JSON(value))
case .failure(let error) :
let error = error as Error
print(error.localizedDescription)
completion(nil)
}
}
}
但是,当我使此函数静态时,我收到错误"调用中的额外参数'方法'"。我已经尝试了具有类似问题的帖子中列出的解决方案,但没有积极的结果。知道可能导致此问题的原因吗?
问题暂时
解决。这是一个范围问题,baseURL
变量不在方法内。以下内容将为我构建。
func registerUser(firstName: String, lastName: String, email: String, username: String, password: String, profilePicture: String, completion: @escaping(JSON?) -> ()) {
let baseURL = "url"
let params: [String:Any]? = [
"first_name" : firstName,
"last_name" : lastName,
"email" : email,
"username" : username,
"password" : password,
"profile_pic" : profilePicture
]
Alamofire.request("(baseURL)/users/create", method: .post, parameters: params, encoding: JSONEncoding.default, headers: nil).responseJSON { response in
switch response .result {
case .success(let value) :
completion(JSON(value))
case .failure(let error) :
let error = error as Error
print(error.localizedDescription)
completion(nil)
}
}
}