在C#中可视化具有文件路径的文件字典的最佳实践

Question

我在C#中有一个由2个字符串组成的Dictionary，它表示文件名和路径。我想将这些可视化为一个表单，其中文件夹的TreeView和实际文件夹的相关文件的ListView。因此，这应该将字典中的数据作为文件浏览器呈现如下：

Dictionary<string, string> dict = new Dictionary<string, string>();
dict.Add("File1","Folder1\Folder2");
dict.Add("File2","Folder1\Folder2\Folder3");
dict.Add("File3","Folder1");
dict.Add("File4","Folder1\Folder2");

我正在寻找一个好的实现来将其呈现为一种形式：

public MethodBrowserForm(Dictionary<string, string> filesAndFolders)
{
InitializeComponent();

string lastMethodFolder = "";
Dictionary<int, List<string>> folderDictionary = new Dictionary<int, List<string>>();

foreach (var method in filesAndFolders)
{
// Compare Key Values for Folders
if (!lastMethodFolder.Equals(method.Value))
{
// Extract Folder
string[] directories = filesAndFolders.Value.Split(Path.DirectorySeparatorChar);
if (directories.Length > 1 )
// First Level Folders

{
// Implementation for Visualization
}

}

lastMethodFolder = filesAndFolders.Value;

}   
}

Answer 1

尝试以下操作：

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace WindowsFormsApplication62
{
public partial class Form1 : Form
{

public Form1()
{
InitializeComponent();
Dictionary<string, string> dict = new Dictionary<string, string>();
dict.Add("File1", "Folder1\Folder2");
dict.Add("File2", "Folder1\Folder2\Folder3");
dict.Add("File3", "Folder1");
dict.Add("File4", "Folder1\Folder2");
List<KeyValuePair<string, List<string>>> files = dict.Select(x => new KeyValuePair<string, List<string>>(x.Key, x.Value.Split(new char[] {'\'}).ToList())).ToList();
TreeNode root = new TreeNode();
CreateTree(null, files);
treeView1.ExpandAll();

}
public void CreateTree(TreeNode node, List<KeyValuePair<string, List<string>>> files)
{
var folders = files.GroupBy(x => x.Value.First()).ToList();
foreach (var folder in folders)
{
TreeNode newNode = new TreeNode(folder.Key);
if (node == null)
{
treeView1.Nodes.Add(newNode);
}
else
{
node.Nodes.Add(newNode);
}
List<KeyValuePair<string, List<string>>> child = new List<KeyValuePair<string, List<string>>>();
foreach (KeyValuePair<string, List<string>> file in folder)
{
if (file.Value.Count == 1)
{
newNode.Nodes.Add(file.Key);
}
else
{
KeyValuePair<string, List<string>> newFile = new KeyValuePair<string, List<string>>(file.Key, file.Value.Skip(1).ToList());
child.Add(newFile);
}
}
if (child != null)
{
CreateTree(newNode, child);
}
}
}


}
}