好吧,我对这个问题已经筋疲力尽了,所以我想我应该得到一些外部帮助。该项目拥有一个人事"数据库",其中包括员工和学生。每个学生都有一个"书"的二叉树,用户可以插入并搜索。我需要取一个学生的名字,找到与该特定学生对应的人员节点,并将一本书添加到该学生的bookTree中。
我收到的错误消息是"Homework4.exe中0x013c53a0处未处理的异常:0xC0000005:读取位置0xcccccd1c的访问冲突。",我认为这意味着我在某个地方弄乱了指针。调用堆栈将第512行(以及book_traverse())显示为问题制造者。这就是我到目前为止所做的(省略了不必要的代码):提前谢谢!
class PersonnelNode { // This is a container class
private:
Personnel *pNode; // It contains a Personnel class
PersonnelNode *pNext; // pointer used to form a linked list
public:
void setNode(Personnel *pNode) { this->pNode = pNode; }
void setNext(PersonnelNode *pNext) { this->pNext = pNext; }
Personnel* getNode() { return pNode; }
PersonnelNode* getNext() { return pNext; }
PersonnelNode() { // constructor
pNode = NULL;
pNext = NULL;
}
} *head = NULL; // declare a global pointer variable head
struct Book {
char title[75];
char url[75];
char key;
Book *left;
Book *right;
Book(char *title, char *url) { // Constructor
strcpy_s(this->title, title);
strcpy_s(this->url, url);
key = title[0];
left = NULL;
right = NULL;
}
};
class Student : public Personnel { //inherit from Personnel
... (omitted the unnecessary code)
Book *bookTree;
//BookTree = NULL in constructor
}
int insert_book() {
PersonnelNode *temp, *prev;
Personnel *person;
Student *student;
Book *newBook;
char title[75], url[75], sName[75];
temp = head;
cout << endl << "@Inserting book node.........." << endl;
cout << "Enter the student name: ";
cin.ignore();
cin.getline(sName, 75);
//*****My error is probably below here?
while (temp != NULL) {
person = temp->getNode();
if (sName != person->getName()) {
prev = temp;
temp = temp->getNext();
}
else {
student = (Student *) person;
}
}
cout << "Enter the book title: ";
cin.getline(title, 75);
cout << "Enter the URL: ";
cin.getline(url, 75);
newBook = new Book(title, url);
book_traverse(student->bookTree, newBook); //LINE 512
return 0;
}
//***Recursive function to insert book
void book_traverse(Book* root, Book* newBook) { //Is this right?
if (root == NULL) //I tried Book* &root, but then
root = newBook; //the compiler doesn't like root==NULL
else if (newBook->key < root->key)
book_traverse(root->left, newBook);
else
book_traverse(root->right, newBook);
}
我想你需要书**
void book_traverse(Book** root, Book* newBook)
然后使用*root而不是处处使用root,例如
*root = newBook
否则,在book_traverse中,您将更改root的本地副本。
声明并初始化必要的变量
- 列出项目
- 读取要插入树中的数据项,比如x
- 创建一个新节点,使其左右指针为null
- 将数据x分配给新节点的信息字段
- 如果(树==NULL)则树=新节点的地址else if(x<tree->info)if(tree->left==NULL)然后树->left=新节点其他的tree=tree->left重复步骤5。else if(x>tree->info)if(tree->right==NULL)然后树->右=新节点其他的tree=tree->right重复步骤5else if(x==tree->info)打印"重复数据"并退出
- 对于下一次插入,转到步骤5
参考:http://www.programmers-point.blogspot.in