Spock异常交互失败，但mockito异常交互有效

Question

我在Spock规范和异常处理方面遇到了问题。

我有一些调用服务并捕获特定类型异常的代码。在catch块中抛出另一种类型的异常:

try { 
   int result = service.invoke(x,y);
   ...
} catch (IOException e) {
   throw BusinessException(e);
}

下面的测试用例使用mockito模型工作:

given: "a service that fails"
def service = mock(Service)
when(service.invoke(any(),any())).thenThrow(new IOException())
and: "the class under test using that service"
def classUnderTest = createClassUnderTest(service)
when: "the class under test does something"
classUnderTest.doSomething()
then: "a business exception is thrown"
thrown(BusinessException)

所有测试通过

，但是当使用Spock处理服务的交互时，以下测试用例失败:

given: "a service that fails"
def service = Mock(Service)
service.invoke(_,_) >> { throw new IOException() }
and: "the class under test using that service"
def classUnderTest = createClassUnderTest(service)
when: "the class under test does something"
classUnderTest.doSomething()
then: "a business exception is thrown"
thrown(BusinessException)

类型为BusinessException的预期异常，但没有抛出异常

我不知道这是怎么回事。这对mockito有用，但对Spock没用。

我没有验证抛出异常的服务，所以它不需要在when/then块中设置。

groovy(使用groovy-all: 2.4.5 spock-core: 1.0 - 2.4)

Answer 1

下面的例子运行得很好:

@Grab('org.spockframework:spock-core:1.0-groovy-2.4')
@Grab('cglib:cglib-nodep:3.1')
import spock.lang.*
class Test extends Specification {
    def "simple test"() {
        given:
            def service = Mock(Service) {
                invoke(_, _) >> { throw new IOException() }
            }
            def lol = new Lol()
            lol.service = service
         when:
            lol.lol()
        then:
            thrown(BusinessException)
    }
}
class Service {
    def invoke(a, b) {
        println "$a $b"
    }
}
class Lol {
    Service service 
    def lol() {
        try {
            service.invoke(1, 2)
        } catch(IOException e) {
            throw new BusinessException(e)
        }
    }
}
class BusinessException extends RuntimeException {
    BusinessException(Exception e) {}
}

也许你配置错了什么?