用户将元素输入到 2D 矢量 c++ 中

Question

我试图实现一种算法，我想由用户将元素输入到 2D 向量中，以便我有一个这样的元素：

reference 1:
1 2 3
3 2 1
1 2 3

所以我想知道如何将元素push_back成 2D 矢量

我的问题在这里：

std::vector<vector<int>> d;
//std::vector<int> d;
cout<<"Enter the N number of ship and port:"<<endl;
cin>>in;
cout<<"Enter preference etc..:n";
for(i=0; i<in; i++){ 
cout<<"ship"<<i+1<<":"<<' ';
    for(j=0; j<in; j++){
    cin>>temp;
    d.push_back(temp);// I don't know how to push_back here!!
    }
}

Answer 1

这是解决方案

std::vector<vector<int>> d;
//std::vector<int> d;
cout<<"Enter the N number of ship and port:"<<endl;
cin>>in;
cout<<"Enter preference etc..:n";
for(i=0; i<in; i++){ 
cout<<"ship"<<i+1<<":"<<' ';
    for(j=0; j<in; j++){
    cin>>temp;
    d[i].push_back(temp); 
    }
}

Answer 2

C++是一种

强类型语言，d是向量的向量：

for(i=0; i<in; i++){ 
    cout<<"ship"<<i+1<<":"<<' ';
    vector<int> row;
    for(j=0; j<in; j++){
      cin>>temp;
      row.push_back(temp);// I don't know how to push_back here!!
    }
    d.push_back(row);
}

Answer 3

这应该有效：

vector<vector<int> > d;
int val;
for(int i = 0; i < in; i++){
    vector<int> temp;
    for(int j = 0; j < in; j++){
        cin >> val;
        temp.push_back(val);
    }
    d.push_back(temp);
    temp.clear();
}

Answer 4

通常，我们可以根据类似的方法在向量的 2D 矩阵中添加元素，如下所示：

#include<bits/stdc++.h>  
using namespace std;
int main() {
int row,col;
cin>>row>>col;
vector<vector<int>>matrix;
for(int i=0;i<row;i++){
vector<int>temp;
for(int j=0;j<col;j++){
int val;
cin>>val;
temp.push_back(val);
}
matrix.push_back(temp);
}
return 0;
}

Answer 5

d[x].push_back(y);

这应该适合您。

Answer 6

有两种方法可以执行此任务：

vector<vector<int> > v;
for(int i=0;i<n;i++){
for(int j=0;j<m;j++){
v[i].push_back(data);
}}
vector<vector<int> > v;
for(int i=0;i<n;i++){
vector<int> x;
for(int j=0;j<m;j++) x[j].push_back(data);
v.push_back(x);
}

Answer 7

/* Below takes user input for n x n array */ 
vector<vector <int>> arr(n);  
for (int i = 0; i < n; i++) {  
    arr[i].resize(n);  
    for (int j = 0; j < n; j++) {  
        cin >> arr[i][j];  
    }  
}  

Answer 8

这是你可以做的

int in;
std::cout << "Enter the N number of ship and port:" << std::endl;
std::cin >> in;
// declare a vector d of size 'in' containing vectors of size 0;
std::vector<std::vector<int>> d(in, std::vector<int>());
std::cout << "Enter preference etc..:n";
for(i=0; i<in; i++){ 
    std::cout << "ship" << i+1 << ":" << ' ';
    for(j=0; j<in; j++){
        int temp;
        std::cin >> temp;
        d[i].push_back(temp); // now you can push_back here!!
    }
}

Answer 9

#include <iostream>
#include <vector>
using namespace std;
int main() {
    int N;
    cout << "Please enter the no. of edges: ";
    cin >> N;
    vector<vector<int>> outer;
    for(int i = 0; i < N; i++)
    {
        vector<int> temp;
        for(int j = 0; j < 1; j++)
        {
            int u, v;
            cin >> u;
            cin >> v;
            temp.push_back(u);
            temp.push_back(v);
        };
        outer.push_back(temp);
        temp.clear();
    };
    
    for(int i = 0; i<outer.size(); i++)
    {
        for(int j = 0; j < outer[i].size(); j++)
        {
            cout<<" "<<outer[i][j];
        };
        cout<<endl;
    };
};

Answer 10

//this is a solution and it litrally works give it a try
//v(n) is must 
//thats why your sol was giving problem
//we must specify rows
int main()
{
  int value;
  vector<vector<int>> v(n);
  for(int i=0;i<n;++i)
  {
    for(int j=0;j<n;++j)
    {
      cin>>value;
      v[i].push_back(value);
    }
  }
  return 0;
}

Answer 11

vector<vector<int>> matrix; //declaring 2D vactor as matrix
int val;
cin>>val; //reading size of matrix in val
for(int i=0;i<val;i++){
    vector<int> temp; //make temp vector for storing val for every iteration 
    for(int j=0;j<val;j++){
        int x;
        cin>>x;
        temp.emplace_back(x);
    }
    matrix.emplace_back(temp); // push back to matrix, temp vector's all value for every iteration
    temp.clear(); // clear temp vector for every iteration
}