Android-点击时，燃烧通知打开活动

Question

我正在尝试打开应用程序并在单击"推送通知"时显示通知数据。到目前为止，我拥有的代码是唯一的问题是，当我有两个或多个通知时，应用程序仅显示一个(收到的最新通知(，而不是在通知视图中显示所有单个通知。另外，如果我收到了更多通知并单击它，则应用程序始终将接收到的第一个数据值。

我应该如何正确设置此设置，以便获得收到的所有通知的列表，以及单击将加载正确的数据之一？

private void sendNotification(String image, String title, String subtitle, String content, String url, String time, String category) {
        //RemoteMessage.Notification notification = remoteMessage.getNotification();
        Intent intent = null;
        PendingIntent pendingIntent;
        if (url.equals("")) { // Simply run your activity
            intent = new Intent(this, MainActivity.class);
            intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
        } else { // open a page
            if (!url.equals("")) {
                intent = new Intent(this, NewsNotificationActivity.class);
                intent.putExtra("image", image);
                intent.putExtra("title", title);
                intent.putExtra("subtitle", subtitle);
                intent.putExtra("content", content);
                intent.putExtra("url", url);
                intent.putExtra("time", time);
                intent.putExtra("category", category);
                intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            }
        }
        pendingIntent = PendingIntent.getActivity(this, 0 /* Request code */, intent,
                PendingIntent.FLAG_ONE_SHOT);

        Uri defaultSoundUri= RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
        NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this)
                .setSmallIcon(R.drawable.loading_icon)
                //.setContentTitle(notification.getTitle())
                .setContentTitle(title)
                .setContentText(subtitle)
                .setAutoCancel(true)
                .setSound(defaultSoundUri)
                .setContentIntent(pendingIntent);
        NotificationManager notificationManager =
                (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
        notificationManager.notify(0, notificationBuilder.build());
    }
}

我的php服务器文件： -

$fields = [
            'to'           => '/topics/test2',
            'data' => [
                "image" => "https://example.com/image.png",
                "title" => "aaaaaaa",
                "subtitle" => "bbbbbbb",
                "content" => "ccccc",
                "url" => "https://example.com/news90789/",
                "time" => "dddd",
                "category" => "rrrrrr"
            ]
        ];

Answer 1

您需要在通知

时使用不同的通知ID

notificationManager.notify(0, notificationBuilder.build());
// should be different.   ^^

notify(int ID，通知通知(

发布要在状态栏中显示的通知。如果通知 `您的应用程序已经发布了相同的ID，并且 尚未取消，它将被更新的信息替换。

so

int id = 0; 
notificationManager.notify(id++, notificationBuilder.build());
// should be different.   ^^
// you can use shared preference to keep track of id 
// so that in future you can cancel it via java code

Answer 2

它仅显示一个：

notificationManager.notify(0, notificationBuilder.build());

将其更改为：

int num = (int) System.currentTimeMillis();
notificationManager.notify(num, notificationBuilder.build());

通知ID对于每个通知都应唯一。现在，您将不只有一个通知，因为它们互相覆盖，这就是为什么当您单击通知时，您只有第一个值。