Java:将单个数组除以对象元素值为 2 个数组

Question

编辑。谢谢。

我有一系列"普通"车辆和"大型"车辆。我有一个任务，要求我将它们分开，为一个更大的应用程序做出贡献。 一个数组用于大型车辆，一个用于普通车辆，其中包含每个元素的所有信息。数组列表是不允许的，因为我的老师正在教我们基础知识。

数组示例

27723 4/09/61 large 7337 28507 22-02-1983 large 7055 28558 1/05/70 normal 3518

//On button press
//recieve single item from array from main and test it
//array in main will be looped for all elements. 
public String loadVehicle(Vehicle v) {
String res = Constants.OK;
boolean normBool = false;
boolean largeBool = false;
//if both arrays are full , stop the method call in the main form
if (normBool && largeBool){return Constants.ERROR;}
//if vehicle size is normal, fill the normal veh array
if(v.getSize().equals(Constants.NORMAL_SIZE))
{
for(int i = 0; i<normalVehicles.length; i++)
{
//if norm veh array element is null, add the appropriate value to it
if(normalVehicles[i] == null){normalVehicles[i] = v;}
else{normBool = true;}
}
}
//if veh size is large put it in the large veh array
else if(v.getSize().equals(Constants.LARGE_SIZE))
{   
for(int iL = 0; iL<largeVehicles.length; iL++)
{
if(largeVehicles[iL] == null){largeVehicles[iL] = v;}
else{largeBool = true;}
}
}
return res;
}//end method

Answer 1

似乎你也不能使用内置的LinkedList类，然后这样做：

在车辆类中添加以下代码：

class Vehicle(){
//YOUR OTHER PIECES OF CODES ...
private static Vehicle firstLargeVehicle;
private Vehicle nextLargeVehicle;
private int index;
public void setIndex(int index){
this.index = index;
if(index == 0) Vehicle.firstLargeVehicle = this;
}
public int getIndex(){
return index;
}
public void setNextLargeVehicle(Vehicle nextLargeVehicle){
this.nextLargeVehicle = nextLargeVehicle;
}
public Vehicle getNextLargeVehicle(){
return nextLargeVehicle;
}
public addLargeVehicle(Vehicle newVehicle){
this.nextLargeVehicle = newVehicle;
newVehicle.setIndex(index + 1);
}
public getListSize(){
Vehicle lastOne = this;
while (lastOne.getNextLargeVehicle() != null){
lastOne = lastOne.getNextLargeVehicle();
}
return lastOne.getIndex() + 1;
}
public static Vehicle[] largeVehiclesToArray(){
Vehicle[] result = new Vehicle[firstLargeVehicle.getListSize()]();
Vehicle pointer = firstLargeVehicle;
for (int counter = 0; pointer != null; counter ++){
result[counter] = pointer;
pointer = pointer.getNextLargeVehicle();
}
return result;
}
}

在主循环中，执行类似于以下代码的操作：

Vehicle vehicle = null; 
for(Vehicle newVehicle : allVehicles) {
if (newVehicle.isLarge()){
if (vehicle == null) {
vehicle = newVehicle;
vehicle.setIndex(0);
}else{
vehicle.addLargeVehicle(newVehicle));
}
} 
} 
Vehicle[] largeVehicles = Vehicle.largeVehiclesToArray();

同样的故事也适用于普通车辆。 有什么问题吗？

Answer 2

你可以像这样编写循环：

for(int i = 0; i < normalVehicles.length; i++)
{
if(normalVehicles[i] == null)
{
normalVehicles[i] = v;
break;
}
}
// if last slot isn't null then it's full
normBool = normalVehicles[normalVehicles.length-1] != null;