节点sql解析器，parser.astify(sqlquery)未返回准确的输出

Question

我正试图使用nodesql解析器在nodejs中解析一个sql查询。

const {Parser} = require('node-sql-parser');
const parser = new Parser();
const ast = parser.astify(sqlQuery)

使用的sqluery低于

SELECT * FROM SUBSCRIPTION WHERE COLUMN_1 = 'NORM' AND COLUMN_2 IN ('11','12','13','14','15','16','17','18','42','43','44','45','101','102','103','104','128','129','130','131','159') AND (COLUMN_3 IS NOT NULL OR COLUMN_4 = 1) AND COLUMN_5 <> 1 AND (COLUMN_6 <> '8088' AND COLUMN_7 <>  '9088') 

解析时我得到输出

{ with: null,
type: 'select',
options: null,
distinct: null,
columns: '*',
from: [ { db: null, table: 'SUBSCRIPTION', as: null } ],
where:
{ type: 'binary_expr',
operator: 'AND',
left:
{ type: 'binary_expr',
operator: 'AND',
left: [Object],
right: [Object] },
right:
{ type: 'binary_expr',
operator: 'AND',
left: [Object],
right: [Object],
parentheses: true } },
groupby: null,
having: null,
orderby: null,
limit: null }

我无法在左边迭代的地方：[Object]。有没有什么方法可以解析它，只得到一个运算符列表？

Answer 1

您将其记录为对象，这就是您在其中看到对象的原因。您需要先JSON.stringify(ast)对象，然后再进行合并以查看所有内容。

关于查找所有操作员，您可以使用此代码

const sqlQuery = "SELECT * FROM SUBSCRIPTION WHERE COLUMN_1 = 'NORM' AND COLUMN_2 IN ('11','12','13','14','15','16','17','18','42','43','44','45','101','102','103','104','128','129','130','131','159') AND (COLUMN_3 IS NOT NULL OR COLUMN_4 = 1) AND COLUMN_5 <> 1 AND (COLUMN_6 <> '8088' AND COLUMN_7 <>  '9088')";
const {Parser} = require('node-sql-parser');
const parser = new Parser();
const ast = parser.astify(sqlQuery)
function getOperator(obj, result = []) {
let value;
Object.keys(obj).forEach(key => {
value = obj[key];
if (value instanceof Object) {
getOperator(value, result);
} else if (key === "operator") {
result.push(value);
}
});
return result;
}
console.log(getOperator(ast));
// output will be -  ["AND", "AND","AND","AND","=","IN","OR","IS NOT","=","<>","AND","<>","<>"]