我一直在尝试拆分一个n维数组。我想把它分成100//3(=33(的倍数
我想把长度为100的数组分成3组,这样组1来自索引0-33第二组是34-66第3组来自67-100
这就是我尝试过的。
numberblocks=3
array=np.arange(17)
splitat=len(array)//3
for i in range(1,numberblocks):
np.split(array, splitat*i)
然而,这并没有产生任何产出。这个逻辑有错吗?我该如何做到这一点。?
您只需使用:
np.array_split(array, n)
如果可能的话,将阵列array
拆分为相等的n
部分,如果不可能,最后一次拆分将小于其余部分
在您的情况下,
>>> array = np.arange(100)
>>> split_arrs = np.array_split(array, 3)
>>> split_arrs
[array([ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16,
17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33]), array([34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50,
51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66]), array([67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83,
84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99])]
>>> split_arrs[0]
array([ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16,
17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33])
>>> split_arrs[1]
array([34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50,
51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66])
>>> split_arrs[2]
array([67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83,
84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99])