在android上解析Facebook graph API请求时没有获得照片链接

Question

我正在尝试使用Facebook SDK 4.0和图形API在android上获得用户照片链接。我写了这段代码来解析和获取照片link -

new GraphRequest(
            AccessToken.getCurrentAccessToken(),
                    "/" + userId + "/photos",
                    null,
                    HttpMethod.GET,
                    new GraphRequest.Callback() {
                        public void onCompleted(GraphResponse response) {
                            JSONObject json = null;
                            try {
                                json = new JSONObject(String.valueOf(response));
                            } catch (JSONException e) {
                                e.printStackTracegetJSONObject();
                            }
                            JSONArray jarray = null;
                            try {
                                jarray = json.getJSONArray("data"); 
                            } catch (JSONException e) {
                                e.printStackTrace();
                            } 
                            for(int i = 0; i < jarray.length(); i++){
                                oneAlbum = null;
                                try {
                                    oneAlbumURL1 = jarrayjson.getJSONObjectgetString(i"url");
                                } catch (JSONException e) {
                                    einfo.printStackTracesetText(URL1.toString());
                                }
                                String URL1 = null; // 
                                try {
                                  URL1 = String.valueOf(oneAlbum.getJSONObject("link"));
                                } catch (JSONException e) {
                                    e.printStackTrace();
                                }
                                Log.d("", URL1);
                            }
                        }
                    }
            ).executeAsync();

但是它既没有显示任何错误也没有得到任何url/链接。谁能告诉我这里出了什么问题?

Answer 1

根据新的Facebook api v2.4，您需要传递字段参数与您的Facebook api url。

:和字段=源id、图片

即:

https://graph.facebook.com/userId/photos?access_token=APP_ACCESS_TOKEN&fields=source,id,picture

您将在source和picture标签中获得图像url ..

编辑

Bundle parameters = new Bundle();
parameters.putString("fields", "source,id,picture");
AccessToken.getCurrentAccessToken(),
                    "/" + userId + "/photos",
                    parameters,
                    HttpMethod.GET,

EDIT-2:

public void onCompleted(GraphResponse response) {
    JSONObject json = response.getJSONObject();
    JSONArray jarray = null;
    try {
        jarray = json.getJSONArray("data");
    } catch (JSONException e) {
        e.printStackTrace();
    }

Answer 2

根据v.j.给出的答案，我编辑了我的代码，现在它工作得很好。只是将"url"替换为"source"。

new GraphRequest(
                AccessToken.getCurrentAccessToken(),
                         "/" + userId + "/photos",
                        parameters,
                        HttpMethod.GET,
                        new GraphRequest.Callback() {
                            public void onCompleted(GraphResponse response) {
                                json = response.getJSONObject();
                                Log.d("json value", json.toString());
                                try {
                                    jarray = json.getJSONArray("data");

                                } catch (JSONException e) {
                                    e.printStackTrace();
                                }
                                for(int i = 0; i < jarray.length(); i++){
                                    try {
                                        oneAlbum = jarray.getJSONObject(i);
                                    } catch (JSONException e) {
                                        e.printStackTrace();
                                    }
                                    try {
                                        URL1 = String.valueOf(oneAlbum.getJSONObject("source"));
                                        info.setText(URL1);
                                        Log.d("got URLSSSs", URL1.toString());
                                    } catch (JSONException e) {
                                        e.printStackTrace();
                                    }
                                }
                            }
                        }
                ).executeAsync();