我的安卓应用程序在收到消息时首先显示一个 toast,当它收到来自特定号码的消息时,它会显示另一个 toast。但它没有显示第二个祝酒词。
这是我的代码:
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.os.Bundle;
import android.telephony.SmsManager;
import android.telephony.SmsMessage;
import android.util.Log;
import android.widget.Toast;
public class IncomingSms extends BroadcastReceiver {
// Get the object of SmsManager
final SmsManager sms = SmsManager.getDefault();
public void onReceive(Context context, Intent intent) {
// Retrieves a map of extended data from the intent.
final Bundle bundle = intent.getExtras();
try {
if (bundle != null) {
final Object[] pdusObj = (Object[]) bundle.get("pdus");
for (int i = 0; i < pdusObj.length; i++) {
SmsMessage currentMessage = SmsMessage.createFromPdu((byte[]) pdusObj[i]);
String phoneNumber = currentMessage.getDisplayOriginatingAddress();
String senderNum = phoneNumber;
String message = currentMessage.getDisplayMessageBody();
Log.i("SmsReceiver", "senderNum: "+ senderNum + "; message: " + message);
int duration = Toast.LENGTH_SHORT;
Toast toast = Toast.makeText(context, "senderNum: "+ senderNum + ", message: " + message, duration);
toast.show();
String serverNumber= "+919886096376";
if(senderNum == serverNumber)
{
Toast toast1 = Toast.makeText(context,"alert message received!!!!",Toast.LENGTH_LONG);
toast.show();
}
} // end for loop
} // bundle is null
} catch (Exception e) {
Log.e("SmsReceiver", "Exception smsReceiver" +e);
}
}
}
你以错误的方式比较if(senderNum == serverNumber)
。在Java和Android中,==
用于比较objects
而不是字符串。当您想比较两个字符串时,您需要使用.equals()
方法。
你需要像下面这样比较,
if(senderNum.equals(serverNumber))
{
Toast toast1 = Toast.makeText(context,"alert message received!!!!",Toast.LENGTH_LONG);
toast1.show(); // change this to toast1
}
更改此内容
if(senderNum == serverNumber){
Toast toast1 = Toast.makeText(context,"alert message received!!!!",Toast.LENGTH_LONG);
toast.show();
}
对此
if(senderNum.equals(serverNumber)){
Toast toast1 = Toast.makeText(context,"alert message received!!!!",Toast.LENGTH_LONG);
toast1.show();
}
您没有在正确的吐司上调用节目。
此外,比较 2 个字符串的正确方法如下:
senderNum.equals(serverNumber)
通过使用 ==
运算符,您正在比较对 String 对象的引用,因此它很可能会返回 false。