我正在开发Angular应用程序。我尝试使用 ng-if 并在 ng-repeat 中切换,但没有成功。我有这样的数据:
**[{"_id":"52fb84fac6b93c152d8b4569",
"post_id":"52fb84fac6b93c152d8b4567",
"user_id":"52df9ab5c6b93c8e2a8b4567",
"type":"hoot",},
{"_id":"52fb798cc6b93c74298b4568",
"post_id":"52fb798cc6b93c74298b4567",
"user_id":"52df9ab5c6b93c8e2a8b4567",
"type":"story",},
{"_id":"52fb7977c6b93c5c2c8b456b",
"post_id":"52fb7977c6b93c5c2c8b456a",
"user_id":"52df9ab5c6b93c8e2a8b4567",
"type":"article",},**
$scope.注释 = 上述
数据和我的 Html 像:
<div ng-repeat = "data in comments">
<div ng-if="hoot == data.type">
//differnt template with hoot data
</div>
<div ng-if="story == data.type">
//differnt template with story data
</div>
<div ng-if="article == data.type">
//differnt template with article data
</div>
</div>
我怎样才能在 Angular 中实现这个目标?
尝试用引号'
将strings
(hoot
、story
、article
)括起来:
<div ng-repeat = "data in comments">
<div ng-if="data.type == 'hoot' ">
//different template with hoot data
</div>
<div ng-if="data.type == 'story' ">
//different template with story data
</div>
<div ng-if="data.type == 'article' ">
//different template with article data
</div>
</div>
这个也值得注意
<div ng-repeat="post in posts" ng-if="post.type=='article'">
<h1>{{post.title}}</h1>
</div>
我建议将所有模板移动到单独的文件中,并且不要在重复中执行 spagetti
看看这里:
.html:
<div ng-repeat = "data in comments">
<div ng-include src="buildUrl(data.type)"></div>
</div>
.js:
var app = angular.module('plunker', []);
app.controller('MainCtrl', function($scope) {
$scope.comments = [
{"_id":"52fb84fac6b93c152d8b4569",
"post_id":"52fb84fac6b93c152d8b4567",
"user_id":"52df9ab5c6b93c8e2a8b4567",
"type":"hoot"},
{"_id":"52fb798cc6b93c74298b4568",
"post_id":"52fb798cc6b93c74298b4567",
"user_id":"52df9ab5c6b93c8e2a8b4567",
"type":"story"},
{"_id":"52fb7977c6b93c5c2c8b456b",
"post_id":"52fb7977c6b93c5c2c8b456a",
"user_id":"52df9ab5c6b93c8e2a8b4567",
"type":"article"}
];
$scope.buildUrl = function(type) {
return type + '.html';
}
});
http://plnkr.co/edit/HxnirSvMHNQ748M2WeRt?p=preview