我正在使用可引导的模型trait为使用我的trait的模型注册某些事件。然而,我在尝试模拟使用该特性的模型时遇到了一个问题。具体来说,当模型的Mockery版本被实例化时,它的启动代码同意它应该有一个bootMyTrait方法,但当它试图调用它时却找不到它
下面的示例存储库,其中包含要复制的命令。
举个例子,这里有一个特点:
namespace App;
trait MyTrait
{
public static function bootMyTrait()
{
print("Booting MyTraitn");
}
}
还有一个使用它的模型:
namespace App;
use IlluminateDatabaseEloquentModel;
class MyModel extends Model
{
use MyTrait;
}
定期实例化模型效果良好。这显示了所需的输出:
$model = new MyModel();
然而,试图嘲笑这种模式并不奏效。此:
use IlluminateFoundationTestingWithoutMiddleware;
use IlluminateFoundationTestingDatabaseMigrations;
use IlluminateFoundationTestingDatabaseTransactions;
class ExampleTest extends TestCase
{
/**
* A basic functional test example.
*
* @return void
*/
public function testTraitBooting()
{
$model = $this->getMock('AppMyModel');
}
}
Fails. Adding some debugging to Eloquent:
/**
* Boot all of the bootable traits on the model.
*
* @return void
*/
protected static function bootTraits()
{
$class = static::class;
foreach (class_uses_recursive($class) as $trait) {
print("nTesting that class: $class has method: " . $method = 'boot'.class_basename($trait) . " because of Trait: $traitn");
if (method_exists($class, $method = 'boot'.class_basename($trait))) {
print("Class: $class has method: $method n");
try {
forward_static_call([$class, $method]);
} catch (PHPUnit_Framework_MockObject_BadMethodCallException $e) {
print("Class: $class failed calling $methodn");
throw $e;
}
}
}
}
导致我们失败:
PHPUnit 5.1.0 by Sebastian Bergmann and contributors.
E 1 / 1 (100%)
Testing that class: Mock_MyModel_9ee820db has method: bootMyTrait because of Trait: AppMyTrait
Class: Mock_MyModel_9ee820db has method: bootMyTrait
Class: Mock_MyModel_9ee820db failed calling bootMyTrait
Time: 129 ms, Memory: 18.00Mb
There was 1 error:
1) ExampleTest::testTraitBooting
PHPUnit_Framework_MockObject_BadMethodCallException:
mock-bootable-laravel-model-trait/vendor/laravel/framework/src/Illuminate/Database/Eloquent/Model.php:326
mock-bootable-laravel-model-trait/vendor/laravel/framework/src/Illuminate/Database/Eloquent/Model.php:309
mock-bootable-laravel-model-trait/vendor/laravel/framework/src/Illuminate/Database/Eloquent/Model.php:296
mock-bootable-laravel-model-trait/vendor/laravel/framework/src/Illuminate/Database/Eloquent/Model.php:277
mock-bootable-laravel-model-trait/tests/ExampleTest.php:16
我还尝试过用几种不同的方式创建mock。以DatabaseSoftDeletingTraitTest为例:
use IlluminateFoundationTestingWithoutMiddleware;
use IlluminateFoundationTestingDatabaseMigrations;
use IlluminateFoundationTestingDatabaseTransactions;
use Mockery as m;
class ExampleTest extends TestCase
{
/**
* A basic functional test example.
*
* @return void
*/
public function testTraitBooting()
{
$mock = m::mock('AppMyModel');
$mock->shouldReceive('bootMyTrait')->once();
}
}
但在这里,bootMyTrait从未被称为:
PHPUnit 5.1.0 by Sebastian Bergmann and contributors.
E 1 / 1 (100%)
Time: 149 ms, Memory: 19.25Mb
There was 1 error:
1) ExampleTest::testTraitBooting
MockeryExceptionInvalidCountException: Method bootMyTrait() from Mockery_0_App_MyModel should be called
exactly 1 times but called 0 times.
mock-bootable-laravel-model-trait/vendor/mockery/mockery/library/Mockery/CountValidator/Exact.php:37
mock-bootable-laravel-model-trait/vendor/mockery/mockery/library/Mockery/Expectation.php:271
mock-bootable-laravel-model-trait/vendor/mockery/mockery/library/Mockery/ExpectationDirector.php:120
mock-bootable-laravel-model-trait/vendor/mockery/mockery/library/Mockery/Container.php:297
mock-bootable-laravel-model-trait/vendor/mockery/mockery/library/Mockery/Container.php:282
mock-bootable-laravel-model-trait/vendor/mockery/mockery/library/Mockery.php:142
mock-bootable-laravel-model-trait/vendor/laravel/framework/src/Illuminate/Foundation/Testing/TestCase.php:122
因此,我可以将在引导方法中执行的代码移动到ServiceProvider,但随后我需要注册使用该特性的每个Model。这感觉很脏,使用引导方法似乎很合适。所以我认为我要么遇到了一个错误,要么是错误地使用了模型来嘲笑这个特性。我已经看了getMockForTrait
,但我还需要一个模拟实例来扩展Eloquent(一些特性的方法称为雄辩方法)
如果有人看到我错过的东西(或者如果我完全错了方向),非常感谢
经过一些测试,我相信这样的方法足以测试它:
$mock = m::mock('AppMyModel')->makePartial();
$mock->shouldReceive('bootMyTrait')->once();
$mock->__construct();
说明:
$mock = m::mock('AppMyModel')->makePartial();
我们创建mock,但我们将其作为部分,因为我们希望使用默认的类构造函数和其他方法。使其部分化意味着我们不覆盖的所有方法都将从原始
AppMyModel
类中使用$mock->shouldReceive('bootMyTrait')->once();
这应该是显而易见的——我们想验证
bootMyTrait
方法是否正好运行1次$mock->__construct();
通过这种方式,我们可以运行默认的类构造函数。在创建mock时,似乎没有使用构造函数,所以我们不能用其他方式测试它。如果我们想确保原始类构造函数被启动,我们需要手动启动对象构造函数方法。