IEEE 双精度格式的数字的二进制表示形式

Question

我需要数字实例的二进制表示。首先，我尝试了toString()带有参数2的数字类的方法。结果是 14 位。（电话号码 9878.658456）然后，我尝试将 Number 实例添加到 ByteArray，如下所示：

    var b:ByteArray = new ByteArray();
    var n :Number = 9878.658456;
    trace(uint(n).toString(2));
    b.writeDouble(n);

然后我尝试读取 8 个字节：

    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));

结果真的很有趣，有一些我不知道如何处理的二进制值。我想我仍然不了解 toString 方法，API 解释对我来说还不够。检索数字实例的IEEE表示形式有什么帮助吗？

Answer 1

最好的解决方案是您自己的解决方案。我想出了这个：

    var b:ByteArray = new ByteArray();
    var n :Number = 9878.658456;
    b.writeDouble(n);
    b.position=0;
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));

您可以从此处检查结果，它工作正常。