我已经创建了这个查询,但我认为它可以进行大量优化......但我不知道怎么做?
这是一个查询,它选择了学生拥有的未完成任务,还选择了计划的任务计数,以及他请求帮助的任务数。
后来我不想要计数,而是他/她请求帮助的答案的整行,但现在我从计数开始,因为这似乎更容易。
有没有人可以解释我如何优化这一点,或者我可以在哪里学习?
SELECT
gu.user_id,
notComplete.count AS notComplete,
planned.count AS planned,
helpNeeded.need AS helpNeeded
FROM
`groups_users` gu
LEFT JOIN(
SELECT
a.created_by AS user_id,
COUNT(1) AS 'count'
FROM
`answers` a
WHERE
a.deleted_at IS NULL AND a.completed_at IS NULL AND a.checked_at IS NULL
GROUP BY
a.created_by
) AS notComplete
ON
notComplete.user_id = gu.user_id
LEFT JOIN(
SELECT
a.created_by AS user_id,
COUNT(1) AS 'count'
FROM
`answers` a
WHERE
a.deleted_at IS NULL
GROUP BY
a.created_by
) AS planned
ON
planned.user_id = gu.user_id
LEFT JOIN(
SELECT
a.created_by AS user_id,
COUNT(1) AS need
FROM
`answers` a
WHERE
a.deleted_at IS NULL AND a.requested_help_at IS NOT NULL
GROUP BY
a.created_by
) AS helpNeeded
ON
helpNeeded.user_id = gu.user_id
INNER JOIN `users` u ON
u.id = gu.user_id AND u.type = 'student'
WHERE
gu.group_id = 213
尝试以下操作
SELECT
gu.user_id,
SUM(IF(a.deleted_at IS NULL AND a.completed_at IS NULL AND a.checked_at IS NULL,1,0)) AS notComplete,
SUM(IF(a.deleted_at IS NULL,1,0)) AS planned,
SUM(IF(a.deleted_at IS NULL AND a.requested_help_at IS NOT NULL,1,0)) AS helpNeeded
FROM `groups_users` gu
JOIN `users` u ON u.id = gu.user_id
LEFT JOIN `answers` a ON a.created_by = gu.user_id
WHERE gu.group_id = 213
AND u.type = 'student'
GROUP BY gu.user_id
针对第二个问题尝试以下操作
SELECT
gu.user_id,
IF(a.deleted_at IS NULL AND a.completed_at IS NULL AND a.checked_at IS NULL,1,0) AS notComplete,
IF(a.deleted_at IS NULL,1,0) AS planned,
IF(a.deleted_at IS NULL AND a.requested_help_at IS NOT NULL,1,0) AS helpNeeded,
a.* -- full answer row
FROM `groups_users` gu
JOIN `users` u ON u.id = gu.user_id
LEFT JOIN `answers` a ON a.created_by = gu.user_id
LEFT JOIN `answer_plannedday` ap ON ap.answer_id = a.id
LEFT JOIN `plannedday` p ON p.id = ap.planned_day_id
WHERE gu.group_id = 213
AND u.type = 'student'
AND STR_TO_DATE(CONCAT(p.year, '-', p.month, '-', p.day), '%Y-%m-%d') BETWEEN STR_TO_DATE('2016-12-01', '%Y-%m-%d') AND STR_TO_DATE('2018-04-13', '%Y-%m-%d')
如果您只想获取 notComplete 的详细信息,您可以将所有必要条件放入 WHERE 中
SELECT
gu.user_id,
a.* -- full answer row
FROM `groups_users` gu
JOIN `users` u ON u.id = gu.user_id
LEFT JOIN `answers` a ON a.created_by = gu.user_id
LEFT JOIN `answer_plannedday` ap ON ap.answer_id = a.id
LEFT JOIN `plannedday` p ON p.id = ap.planned_day_id
WHERE gu.group_id = 213
AND u.type = 'student'
AND STR_TO_DATE(CONCAT(p.year, '-', p.month, '-', p.day), '%Y-%m-%d') BETWEEN STR_TO_DATE('2016-12-01', '%Y-%m-%d') AND STR_TO_DATE('2018-04-13', '%Y-%m-%d')
-- you say here that you want to get only these rows
AND a.deleted_at IS NULL AND a.completed_at IS NULL AND a.checked_at IS NULL