如何基于属性将JavaScript数组拼接

Question

我在AngularJS网格中获得了一系列数据，我需要删除所有具有相同Custcountry的行

ex-我的客户数组看起来像

  Customer[0]={ CustId:101 ,CustName:"John",CustCountry:"NewZealand" };
  Customer[1]={ CustId:102 ,CustName:"Mike",CustCountry:"Australia" };
  Customer[2]={ CustId:103 ,CustName:"Dunk",CustCountry:"NewZealand" };
  Customer[3]={ CustId:104 ,CustName:"Alan",CustCountry:"NewZealand" };

因此，在网格中，如果CustomerCountry为newzealand

，我需要删除这三个记录

我正在使用剪接方法，让我知道如何通过justomercountry剪接

来使用

 $scope.remove=function(CustCountry)
{
    $scope.Customer.splice(index,1);
 }

Answer 1

如果您可以拿回副本，这是.filter的完美用例：

Customer = [
  { CustId:101 ,CustName:"John",CustCountry:"NewZealand" },
  { CustId:102 ,CustName:"Mike",CustCountry:"Australia" },
  { CustId:103 ,CustName:"Dunk",CustCountry:"NewZealand" },
  { CustId:104 ,CustName:"Alan",CustCountry:"NewZealand" },
]
console.log(Customer.filter(cust => cust.CustCountry !== "NewZealand"));

Answer 2

如果您有一个特定的国家，则只需使用.filter（）

$scope.Customer = $scope.Customer.filter(obj => obj.CustCountry !== "SpecificCountry")

如果要删除具有重复国家/地区的所有对象，请参考从JS数组中删除重复值，这就是您可以做的：

var removeDuplicateCountries = function(arr){
    var dupStore = {};
    for (var x= 0; x < arr.length; x++){
        if (arr[x].CustCountry in dupStore){
            dupStore[arr[x].CustCountry] = false;
        } else {
            dupStore[arr[x].CustCountry] = true;
        }
    }

    var newarr = [];
    for (var x= 0; x < arr.length; x++){
        if (dupStore[arr[x].CustCountry]){
            newarr.push(arr[x]);
        }
    }
    return arr;
};
$scope.Customer = removeDuplicateCountries($scope.Customer);

或合并.filter（）方法

var removeDuplicateCountries = function(arr){
    var dupStore = {};
    var newarr = arr;
    for (var x= 0; x < arr.length; x++){
        if (arr[x].CustCountry in dupStore){
            newarr = newarr.filter(obj => obj.CustCountry !== arr[x].CustCountry);
        } else {
            dupStore[arr[x].CustCountry] = true;
        }
    }
    return newarr;
};
$scope.Customer = removeDuplicateCountries($scope.Customer);

如果有许多重复的国家，则在没有.filter（）