甜蜜警报框我添加4个按钮只有一个按钮正在工作。指向同一框的4个按钮和同一div问题是我们单击时的第一个按钮,弹出窗口是第二个按钮弹出窗口未出现如何解决此问题?
JS:
document.querySelector('ul.examples li.input button').onclick = function(){
swal({
title: "An input!",
text: 'Write something interesting:',
type: 'input',
showCancelButton: true,
closeOnConfirm: false,
animation: "slide-from-top",
inputPlaceholder: "Write something",
},
function(inputValue){
if (inputValue === false) return false;
if (inputValue === "") {
swal.showInputError("You need to write something!");
return false;
}
swal("Nice!", 'You wrote: ' + inputValue, "success");
});
};
html:
<html>
<head>
<script src="https://code.jquery.com/jquery-2.1.3.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/sweetalert/1.1.3/sweetalert.min.js"></script>
<link rel="stylesheet" type="text/css" href="https://cdnjs.cloudflare.com/ajax/libs/sweetalert/1.1.3/sweetalert.min.css">
</head>
<body>
<ul class="examples">
<li class="input"> <div class="ui"> <button> 1 </button> </div> </li> <br>
<li class="input"> <div class="ui"> <button> 2 </button> </div> </li> <br>
<li class="input"> <div class="ui"> <button> 3 </button> </div> </li> <br>
<li class="input"> <div class="ui"> <button> 4 </button> </div> </li> <br>
</ul>
</body>
</html>
<!-- end snippet -->
使用querySelectorall。因为它返回所有元素,所以您应该循环循环返回的值,例如collow
var buttons = document.querySelectorAll('ul.examples li.input button');
for (var i = 0; i < buttons.length; i++) {
buttons[i].onclick = function(){
swal({
title: "An input!",
text: 'Write something interesting:',
type: 'input',
showCancelButton: true,
closeOnConfirm: false,
animation: "slide-from-top",
inputPlaceholder: "Write something",
},
function(inputValue){
if (inputValue === false) return false;
if (inputValue === "") {
swal.showInputError("You need to write something!");
return false;
}
swal("Nice!", 'You wrote: ' + inputValue, "success");
});
};
}
<html>
<head>
<script src="https://code.jquery.com/jquery-2.1.3.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/sweetalert/1.1.3/sweetalert.min.js"></script>
<link rel="stylesheet" type="text/css" href="https://cdnjs.cloudflare.com/ajax/libs/sweetalert/1.1.3/sweetalert.min.css">
</head>
<body>
<ul class="examples">
<li class="input"> <div class="ui"> <button> 1 </button> </div> </li> <br>
<li class="input"> <div class="ui"> <button> 2 </button> </div> </li> <br>
<li class="input"> <div class="ui"> <button> 3 </button> </div> </li> <br>
<li class="input"> <div class="ui"> <button> 4 </button> </div> </li> <br>
</ul>
</body>
</html>
请使用querySelectall。
Array.prototype.forEach.call(document.querySelectorAll('ul.examples li.input button'),function(button){
button.onclick = function(){
swal({
title: "An input!",
text: 'Write something interesting:',
type: 'input',
showCancelButton: true,
closeOnConfirm: false,
animation: "slide-from-top",
inputPlaceholder: "Write something",
},
function(inputValue){
if (inputValue === false) return false;
if (inputValue === "") {
swal.showInputError("You need to write something!");
return false;
}
swal("Nice!", 'You wrote: ' + inputValue, "success");
});
}
});
<html>
<head>
<script src="https://code.jquery.com/jquery-2.1.3.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/sweetalert/1.1.3/sweetalert.min.js"></script>
<link rel="stylesheet" type="text/css" href="https://cdnjs.cloudflare.com/ajax/libs/sweetalert/1.1.3/sweetalert.min.css">
</head>
<body>
<ul class="examples">
<li class="input"> <div class="ui"> <button> 1 </button> </div> </li> <br>
<li class="input"> <div class="ui"> <button> 2 </button> </div> </li> <br>
<li class="input"> <div class="ui"> <button> 3 </button> </div> </li> <br>
<li class="input"> <div class="ui"> <button> 4 </button> </div> </li> <br>
</ul>
</body>
</html>