>我有一个可拖动的列表元素,它可以在拖动时克隆并填充另一个列表。当我放下项目时,我想更改新放下的 li 元素的内容。我遇到的问题是jQuery的这仍然是原始的拖动项,而不是克隆的项。
如何专门定位新克隆的项目,以便我可以更改其内容而不影响列表中的其他项目?
代码如下。感谢您的任何智慧!
.CSS:
<style>
#intro-clone, #assessment-clone {
list-style-type: none;
margin: 0;
padding: 0;
width: 180px;
display: inline-block;
}
#intro-statements, #assessment-statements {
list-style-type: none;
margin: 0;
padding: 0;
width: 365px;
}
#intro-clone li, #assessment-clone li, #intro-statements li, #assessment-statements li {
margin: 0 5px 5px 5px;
padding: 5px;
font-size: 1.2em;
min-height: 25px;
}
#intro-clone li, #assessment-clone li, #intro-statements li, #assessment-statements li {
min-height: 25px;
line-height: 1.2em;
}
.ui-state-highlight {
min-height: 25px;
line-height: 1.2em;
}
ul {
padding: 6px 1px 1px 0 !important;
min-height: 42px;
background: silver;
border-radius: 3px;
}
</style>
.JS:
<script>
$(function() {
$("#intro-statements, #assessment-statements").sortable({
placeholder: "ui-state-highlight",
revert: true
});
$( "#intro-clone li" ).draggable({
drag: function() { $("#intro-clone li").css("width","158px"); },
stop: function() {
$("#intro-statements li").css({"width":"343px","height":"25px"}); // this is applied to ALL the li elements, including the cloned one
console.log(this); // reference's the original drag element, not the clone
window.setTimeout(function() { $(this).html("new content") }, 1000); // doesn't work!
},
connectToSortable: "#intro-statements",
helper: "clone",
revert: "invalid"
});
$( "#assessment-clone li" ).draggable({
drag: function() { $("#assessment-clone li").css("width","158px"); },
stop: function() {
$("#assessment-statements li").css({"width":"343px","height":"50px"}).html("new content<br>new line"); // this is applied to ALL the li elements, including the cloned one
},
connectToSortable: "#assessment-statements",
helper: "clone",
revert: "invalid",
});
$("#intro-statements, #assessment-statements").disableSelection();
$("#show").click(function() {
var intros = {};
$('li', 'ul.sort').each(function(i) {
var $li = $(this);
var $text = $li.text();
var name = $li[0].tagName.toLowerCase();
//intros[name + '-' + i] = $text;
intros[i] = $text;
});
console.log(intros);
$("#show").html(JSON.stringify(intros));
});
});
</script>
.HTML:
<ul id="intro-clone">
<li class="ui-state-default">Intro item</li>
</ul>
<ul id="assessment-clone">
<li class="ui-state-default">Assessment item</li>
</ul>
<br>
<br>
<ul id="intro-statements" class="sort">
</ul>
<br>
<ul id="assessment-statements" class="sort">
</ul>
<div id="show">SHOW</div>
你如何永远试图找到解决方案,然后当你发布寻求帮助时,它就会来找你!
所以这为我做了诀窍:我在拖动事件上将一个类附加到元素。当删除新元素时,我从源元素中删除该类,并将该类定位到新的克隆元素上,并对其进行更改。最后,我从克隆的元素中删除该类以保持其唯一性。
以下是更新的 js:
$( "#intro-clone li" ).draggable({
drag: function() {
$("#intro-clone li").css("width","158px").addClass("new"); // add the new class
},
stop: function() {
$("#intro-clone li").removeClass("new"); // remove it again
$("#intro-statements li.new").css({"width":"343px","height":"25px"});
window.setTimeout(function() { $("#intro-statements li.new").html("new content") }, 1000); // make my changes to the cloned element
window.setTimeout(function() { $("#intro-statements li").removeClass("new") }, 1500); // remove class so it is unique for the next clone
},
connectToSortable: "#intro-statements",
helper: "clone",
revert: "invalid"
});
这可能是很好的代码,也可能不是,但它解决了我的问题,所以我很高兴:)
您需要将stop
添加到sortable
方法中,如下所示sortable
使draggable
和droppable
在一起。我认为这对你更好。
$("#intro-statements, #assessment-statements").sortable({
placeholder: "ui-state-highlight",
revert: true,
stop: function(event, ui) {
console.log(event.target);
}
});