在类中声明动态数组(unsigned char和struct)

Question

在类中声明动态结构体和无符号字符数组的正确方法是什么?

#define GENDER_MALE 0
#define GENDER_FEMALE 1
class c_House {
    public:
        c_House();
        c_House( unsigned int in_BedRoomCount,
                 short in_FloorCount,
                 const char* in_Address,
                 unsigned int in_PeopleCount ) :
                 BedRoomCount( in_BedRoomCount ),
                 FloorCount( in_FloorCount ),
                 Address( in_Address ),
                 PeopleCount( in_PeopleCount )
        {
            this->Array = new unsigned char[ in_BedRoomCount ];
            this->People = new PEOPLE[ in_PeopleCount ];
        };
        ~c_House() { delete[] this->Array; };
    // PROPERTIES
    private:
        struct PERSON {
            unsigned short Age;
            const char* Name;
            unsigned short Gender;
        };
        unsigned int BedRoomCount;
        short FloorCount;
        const char* Address;
        unsigned char* Array;
        unsigned int PeopleCount;
        PERSON *People;
    // ACTIONS
    private:
        void OpenGarage( bool in_Open );
        void Vacuum();
};

我应该如何声明一个动态数组(int和struct)?我知道这将是非常危险的-考虑深度复制等等:

this->Array = new unsigned char[ in_BedRoomCount ];
this->People = new PEOPLE[ in_PeopleCount ];

这是删除int数组的正确方法吗?

~c_House() { delete[] this->Array; };

struct array呢?

Answer 1

正确的方法是用std::string代替char的动态数组，用std::vector<PERSON>代替PERSON的动态数组。

如果在类中动态手动分配数据，则必须确保遵循三规则，即实现复制构造函数、赋值操作符和析构函数来执行数据的"深度复制"。这是为了确保类的每个实例都拥有其动态分配的数据，并使复制和分配安全。在c++ 11中，这被推广为五规则。

一个无关的问题:任何地方包含前导下划线或双下划线的名称都为实现保留。所以你不应该给你的变量命名，比如in__PeopleCount。