使用@FormParam的PUT方法

Question

如果我有这样的内容:

@PUT
@Path("/login")
@Produces({"application/json", "text/plain"})
@Consumes("application/json")
public String login(@FormParam("login") String login, @FormParam("password") String password) throws Exception
{
    String response = null;
    response = new UserManager().login(login, password);
    return response;
}

如何输入这两个参数来测试我的REST服务(在Content字段中)?是不是这样的:

{"login":"xxxxx","password":"xxxxx"}

谢谢

Answer 1

表单参数数据只有在提交时才会显示…表单数据。将资源的@Consumes类型更改为multipart/form-data。

@PUT
@Path("/login")
@Produces({ "application/json", "text/plain" })
@Consumes("multipart/form-data")
public String login(@FormParam("login") String login,
        @FormParam("password") String password) {
    String response = null;
    response = new UserManager().login(login, password);
    return response;
}

然后在客户端设置:

• 内容类型:多部分/格式
• 为login和password添加表单变量

顺便说一下，假设这不是为了学习，您将希望使用SSL保护您的登录端点，并在将密码发送到网络之前对其进行散列。

---

编辑

根据你的评论，我包括一个发送客户端请求和所需表单数据的例子:

try {
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost post = new HttpPost(BASE_URI + "/services/users/login");
    // Setup form data
    List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
    nameValuePairs.add(new BasicNameValuePair("login", "blive1"));
    nameValuePairs.add(new BasicNameValuePair("password",
            "d30a62033c24df68bb091a958a68a169"));
    post.setEntity(new UrlEncodedFormEntity(nameValuePairs));
    // Execute request
    HttpResponse response = httpclient.execute(post);
    // Check response status and read data
    if (response.getStatusLine().getStatusCode() == HttpStatus.SC_OK) {
        String data = EntityUtils.toString(response.getEntity());
    }
} catch (Exception e) {
    System.out.println(e);
}