有没有办法添加到二维数组中的下一个可用空间?(Python 3.x)

Question

Python中有没有办法将数组添加到下一个可用空间？因此，如果 （0,0） 已经有一个值，请转到 （0,1） 并在那里添加值。我走到了下面，我现在被困住了..

class Array:
    def __init__(self):
        self.array = [[0 for x in range(5)] for x in range(5)]
    def view(self):
        for x in self.array:
            print(x)
    def input(self):
        item = input("Enter an item: ")
        self.array[0][0] = item
array = Array()
array.input()
array.view()

Answer 1

这里有一个例子。我只是运行循环 9 次。您应该能够将其处理到您的 OOP 样式代码中。我也在使用标准库中的 pprint 模块，因为我喜欢它显示嵌套列表的方式。

from pprint import pprint as pp

myList = [[0 for x in range(5)] for x in range(5)]
for i in range(9):
    userInput = int(input("Enter an item: "))
    isFound = False # This flag is used to prevent duplicate entries.
    for rowIndex, row in enumerate(myList):
        for colIndex, column in enumerate(row):
            if column == 0 and not isFound:
                myList[rowIndex][colIndex] = userInput
                isFound = True
                break
    pp(myList)

循环最后一次迭代后的输出：（假设始终输入 5）：

Enter an item: 5
[[5, 5, 5, 5, 5],
 [5, 5, 5, 5, 0],
 [0, 0, 0, 0, 0],
 [0, 0, 0, 0, 0],
 [0, 0, 0, 0, 0]]

Answer 2

class Array:
    def __init__(self):
        self.myList = [[0 for x in range(5)] for x in range(5)]
    def input(self):
        print("You will be asked to put a value, if you want to stop, press RETURN key.")
        for i in range(25):
            print()
            userInput = input("Enter an item: ")
            isFound = False

            if userInput == '':
                menu()
            for rowIndex, row in enumerate(self.myList):
                for colIndex, column in enumerate(row):
                    if column == 0 and not isFound:
                        self.myList[rowIndex][colIndex] = userInput
                        isFound = True
                        break

            print()
            for x in self.myList:
                print(x)
    def remove(self):
        print("Which box do you want to delete? Type in coordinates.")
        x = int(input("Please enter a column: "))
        x -= 1
        y = int(input("Please enter a row: "))
        y -= 1
        self.myList[x][y] = 0
        print()
        for i in self.myList:
            print(i)
        menu()
    def view(self):
        for i in self.myList:
            print(i)
        menu()

array = Array()
def menu():
    print()
    print()
    print()
    print("****************")
    print("      MENU")
    print("****************")
    print("Please choose:")
    print("1. Add an item to the array")
    print("2. Remove an item from the array")
    print("3. View array")
    print()
    print("0. Quit")
    print("****************")
    option = int(input("Enter (1, 2 or 0): "))
    print()
    if option == 1:
        array.input()
    elif option == 2:
        array.remove()
    elif option == 3:
        array.view()
    elif option == 0:
        quit()
    else:
        print("Error..")

menu()