我得到一个403禁止的错误。我试过做论坛上已经解释过的上下文的事情,但我仍然坚持到底。
我做错了什么?我的观点.py
def add_player(request, team_id):
template = get_template('cricket/addplayer.html')
loggedinuser = request.user
team = Team.objects.get(id=team_id)
if request.method== 'POST':
form = PlayerForm(request.POST)
if form.is_valid():
player = Player.objects.create(
name = form.cleaned_data['name'],
team = Team.objects.get(id=team_id),
role = form.cleaned_data['role'],
position = form.cleaned_data['position']
)
return HttpResponseRedirect('/team/%s/' % team_id)
else:
form = PlayerForm
page_vars = Context({
'form': form,
'loggedinuser': loggedinuser,
'team': team,
})
output = template.render(page_vars)
return HttpResponse(output)
和我的模板。正如你所看到的,它有{%csrf_token%}
{% extends 'cricket/base.html' %}
{% block title %}
{{ loggedinuser }}
{% endblock %}
{% block username %}
{{ loggedinuser }}
{% endblock %}
{% block date %}
{{ today }}
{% endblock %}
{% block content %}
<div class="span7">
<h2>Adding player for {{ team }}</h2>
<form method="post" action=".">
{% csrf_token %}
{{ form.as_p }}
<input type="submit">
</form>
</div>
{% endblock %}
我很确定我很快就会把脑袋从什么东西上砍下来。
//鼠标
好的,我解决了。你必须使用RequestContext。这是我的解决方案,将原始代码中的最后两行更改为包含crsfcontext
page_vars = Context({
'form': form,
'loggedinuser': loggedinuser,
'team': team,
})
crsfcontext = RequestContext(request, page_vars)
output = template.render(crsfcontext)
return HttpResponse(output)
您还可以在django中使用基于类的通用视图。在你的情况下可能是这样的:(我没有测试它)
urls.py
urlpatterns = patterns('',
url(r'^your-url/(?P<teamId>d+)/$', AddPlayerView.as_view(), name="add-player"),
)
views.py
from django.views.generic import FormView
from django.core.urlresolvers import reverse
.....
class AddPlayerView(FormView):
template_name = 'cricket/addplayer.html'
form_class = PlayerForm
def form_valid(self, form):
""" Code if the form is valid """
...
player = Player.objects.create(
name = form.cleaned_data['name'],
team = Team.objects.get(id=form.cleaned_data['team_id']),
role = form.cleaned_data['role'],
position = form.cleaned_data['position']
)
# You could use url reverse here
url = reverse('your-view-name', args=[form.cleaned_data['team_id']])
return HttpResponseRedirect(url)
def form_invalid(self, form):
""" Code if the form is invalid """
.....
def get_context_data(self, **kwargs):
context = super(AddPlayerView, self).get_context_data(**kwargs)
loggedinuser = self.request.user
team = Team.objects.get(id=self.kwargs['teamId'])
context['loggedinuser'] = loggedinuser
context['team'] = team
return context
尝试使用render_to_response函数,而不是带有一些RequestContext的HttpResponse。