弹簧安全OAuth2在重定向之前操纵请求URL

Question

我有一个使用Spring Security OAuth2保护的Vaadin应用程序。除了偶尔使用的推动或心跳端点用于首先请求并触发身份验证过程，并且用户最终在错误的页面上(用户不应直接访问这些端点(。

简单但不安全的修复是在这些端点上的permitAll()。但是，由于这构成了威胁，我需要关闭这个漏洞。

为此，我想解析并有可能编辑请求URL，然后再在SuccessL auth上重定向到它。我该怎么做？

我想我需要在链中的某个地方添加一个过滤器以拦截请求并进行编辑。但是我不确定在哪里。

这是我的客户：

@Configuration
@EnableOAuth2Sso
public class OAuthConfig extends WebSecurityConfigurerAdapter
{
    @Override
    protected void configure(HttpSecurity http) throws Exception
    {
        http.csrf().disable()
                .authorizeRequests()
                .antMatchers("/login**").permitAll()
                .antMatchers("/vaadinServlet/PUSH/**").permitAll()          //todo fix this hole
                .antMatchers("/vaadinServlet/HEARTBEAT/**").permitAll()      //todo fix this hole
                .anyRequest().authenticated()
                .and()
                .logout()
                .logoutSuccessUrl("/")
                .logoutRequestMatcher(new AntPathRequestMatcher("/logout"));
    }
    @Override
    public void configure(WebSecurity web) throws Exception
    {
        web.ignoring().antMatchers("/css/*").antMatchers("/VAADIN/**"); // Static resources are ignored
    }
}

和服务器：

@Configuration
@EnableAuthorizationServer
public class OAuth2Config extends AuthorizationServerConfigurerAdapter
{
//jwt token stuff & my own client/auth providers. Should not be important.
...
}

服务器登录表格：

@Configuration
public class WebSecurityConfig extends WebSecurityConfigurerAdapter
{
    @Autowired
    private RestAuthenticationProvider authenticationProvider;
    @Override
    public void configure(AuthenticationManagerBuilder auth) throws Exception
    {
        auth.authenticationProvider(authenticationProvider);
    }
    @Override
    protected void configure(HttpSecurity http) throws Exception
    {
        http
                .authorizeRequests()
                .antMatchers(HttpMethod.GET, "/forgetPassword*").permitAll()
                .antMatchers(HttpMethod.POST,"/user/resetPassword*").permitAll()
                .antMatchers(HttpMethod.GET,"/user/changePassword*").permitAll()
                .antMatchers("/user/updatePassword*", "/user/savePassword*", "/updatePassword*")
                .hasAnyAuthority("CHANGE_PASSWORD_PRIVILEGE","ROLE_USER")
                .anyRequest().authenticated()
                .and()
                    .formLogin()
                    .loginPage("/login")
                    .permitAll()
                .and()
                    .csrf().csrfTokenRepository(csrfTokenRepository());
    }
    private CsrfTokenRepository csrfTokenRepository()
    {
        HttpSessionCsrfTokenRepository repository = new HttpSessionCsrfTokenRepository();
        repository.setHeaderName("X-XSRF-TOKEN");
        return repository;
    }
}

Answer 1

只需与您的项目添加一些实现

1：创建身份验证故障处理程序

@Component
public class CustomAuthenticationFailureHandler extends SimpleUrlAuthenticationFailureHandler {

    @Override
    public void onAuthenticationFailure(HttpServletRequest request, HttpServletResponse response, AuthenticationException exception) throws IOException, ServletException {
        System.out.print("here failure");

        String s=request.getParameter("username");
        setDefaultFailureUrl("/login?error&username="+s);
        super.onAuthenticationFailure(request,response,exception);
    }
}

2：身份验证成功处理程序

@Component
public class CustomAuthenticationSuccessHandler extends SimpleUrlAuthenticationSuccessHandler {
    @Override
    public void onAuthenticationSuccess(HttpServletRequest request , HttpServletResponse response, Authentication authentication) throws IOException, ServletException {
        /* custom Block 
Do any thing here
  */
        setDefaultTargetUrl("/home/");
        super.onAuthenticationSuccess(request,response,authentication);
    }
}

3：访问请求输入点

@Component
public class CustomAuthenticationEntryPoint implements AuthenticationEntryPoint {
    @Override
    public void commence(HttpServletRequest httpServletRequest, HttpServletResponse httpServletResponse, AuthenticationException e) throws IOException, ServletException {
        System.out.print("Unauthorized Access");
        httpServletResponse.sendError(HttpServletResponse.SC_UNAUTHORIZED);
    }
}

根据您的要求实现组件。