如何读取用户输入?

Question

我正在编写一个程序，询问用户的感受，并根据用户输入的内容给出不同的响应。例如，如果您很高兴或心情好，它会在屏幕上打印"很高兴听到"。但是，我不知道如何读取用户输入。我应该尝试什么？(** 中的文本是我需要帮助的(。谢谢！

---

`name = input('what is your name?')
print('hello '+ name)
you = input('how are you doing today?')
**if you = happy, good, ok:
print('Glad to hear!')
else:
print('I am sorry, I think I can cheer you up.')**
game = input('wanna play hangman?')    
print('yay! Ill start it up.')
print('hangman starting up...')`    

在此之后，刽子手游戏开始了。

Answer 1

if you in ['good','great','awesome']

是我猜的一种方式......

Answer 2

欢迎来到 StackOverflow！

如果我理解正确，您要做的是字符串比较：

name = input('what is your name?')
print('hello '+ name)
you = input('how are you doing today?')
# ok, we need to compare the input stored in "you"
# first way is to try expected things, and we can lower case it to facilitate.
if you.lower() == 'good' or you.lower() == 'great':
print('Glad to hear!')
# ... rest of the code

或者：

if you.lower() in ['good', 'great', 'awesome']:
print('Glad to hear!')

Answer 3

我相信这就是你需要的：

name = input('what is your name?')
print('hello '+ name)
you = input('how are you doing today?')
if you == 'happy' or you == 'good' or you == 'ok':
print('Glad to hear!')
else:
print('I am sorry, I think I can cheer you up.')
game = input('wanna play hangman?')    
print('yay! Ill start it up.')
print('hangman starting up...')