如何在 python 不和谐机器人中获取用户输入?

Question

我有一个python discord机器人，我需要它在命令后获取用户输入，我该怎么做？我是 python 的新手，正在制作不和谐的机器人。这是我的代码：

import discord, datetime, time
from discord.ext import commands
from datetime import date, datetime
prefix = "!!"
client = commands.Bot(command_prefix=prefix, case_insensitive=True)
times_used = 0
@client.event
async def on_ready():
print(f"I am ready to go - {client.user.name}")
await client.change_presence(activity=discord.Activity(type=discord.ActivityType.watching, name=f"{client.command_prefix}python_help. This bot is made by drakeerv."))
@client.command(name="ping")
async def _ping(ctx):
global times_used
await ctx.send(f"Ping: {client.latency}")
times_used = times_used + 1
@client.command(name="time")
async def _time(ctx):
global times_used
from datetime import date, datetime
now = datetime.now()
if (now.strftime("%H") <= "12"):
am_pm = "AM"
else:
am_pm = "PM"
datetime = now.strftime("%m/%d/%Y, %I:%M")
await ctx.send("Current Time:" + ' '  + datetime + ' ' + am_pm)
times_used = times_used + 1
@client.command(name="times_used")
async def _used(ctx):
global times_used
await ctx.send(f"Times used since last reboot:" + ' ' + str(times_used))
times_used = times_used + 1
@client.command(name="command") #THIS LINE
async def _command(ctx):
global times_used
await ctx.send(f"y or n")
times_used = times_used + 1
@client.command(name="python_help")
async def _python_help(ctx):
global times_used
msg = 'rn'.join(["!!help: returns all of the commands and what they do.",
"!!time: returns the current time.",
"!!ping: returns the ping to the server."])
await ctx.send(msg)
times_used = times_used + 1

client.run("token")

我正在使用python版本3.8.3。我已经看过其他帖子，但他们没有回答我的问题或给我错误。任何帮助将不胜感激！

Answer 1

你会想要使用Client.wait_for()：

@client.command(name="command")
async def _command(ctx):
global times_used
await ctx.send(f"y or n")
# This will make sure that the response will only be registered if the following
# conditions are met:
def check(msg):
return msg.author == ctx.author and msg.channel == ctx.channel and 
msg.content.lower() in ["y", "n"]
msg = await client.wait_for("message", check=check)
if msg.content.lower() == "y":
await ctx.send("You said yes!")
else:
await ctx.send("You said no!")
times_used = times_used + 1

并超时：

import asyncio # To get the exception
@client.command(...)
async def _command(ctx):
# code
try:
msg = await client.wait_for("message", check=check, timeout=30) # 30 seconds to reply
except asyncio.TimeoutError:
await ctx.send("Sorry, you didn't reply in time!")

---

引用：

• Client.wait_for()- 更多示例在这里
• Message.author
• Message.channel
• Message.content
• asyncio.TimeoutError

Answer 2

有了这个，你可以做这样的东西

@client.command()
async def command(ctx):
computer = random.randint(1, 10)
await ctx.send('Guess my number')
def check(msg):
return msg.author == ctx.author and msg.channel == ctx.channel and int(msg.content) in [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
msg = await client.wait_for("message", check=check)
if int(msg.content) == computer:
await ctx.send("Correct")
else:
await ctx.send(f"Nope it was {computer}")

Answer 3

我花了几天时间试图弄清楚这一点，对我来说唯一简单的事情就是将 message.content 存储到列表中并在以后使用它。

some_list = []
user_message = message.content.split()
some_list.append(user_message)

由于我正在使用命令，我想删除该"！"并获取原始消息

for i  in some_list:
del i[0]# delete's command tag