我已经将后台任务功能添加到我的应用程序中。这是我的应用程序代表
// AppDelegate.m
- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {
[self setWindow:[[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]]];
[self.window setBackgroundColor:[UIColor blackColor]];
if (application.applicationState != UIApplicationStateBackground) {
// Application is launch in because user tap the app icon or from springboard
if ([application respondsToSelector:@selector(setMinimumBackgroundFetchInterval:)]) {
[application setMinimumBackgroundFetchInterval:UIApplicationBackgroundFetchIntervalMinimum];
}
} else {
// Application is launch in background mode
}
RootViewController *rootViewController = [[RootViewController alloc] initByDevice];
[self.window setRootViewController:rootViewController];
[self.window makeKeyAndVisible];
return YES;
}
- (void)application:(UIApplication *)application performFetchWithCompletionHandler:(void (^)(UIBackgroundFetchResult))completionHandler {
[[DataManager instance] updateDataWithMaxAttempt:5 block:^(BOOL success, NSArray *newData) {
if (success) {
if ([newData count] > 0) {
completionHandler(UIBackgroundFetchResultNewData);
} else {
completionHandler(UIBackgroundFetchResultNoData);
}
} else {
completionHandler(UIBackgroundFetchResultNoData);
}
}];
}
这是我的根视图控制器
// RootViewController.m
- (void)viewDidAppear:(BOOL)animated {
[super viewDidAppear:animated];
NSLog(@"Did appear");
// Do something that I want it to happen only when the application is visible to user
}
当用户点击应用程序图标时,应用程序的工作方式与我预期的一样。我在控制台上看到"确实出现了",然后事情就如我所料地发生了。
但当应用程序唤醒以执行后台任务(用户不可见)时,RootViewController's
viewDidAppear
仍因该线路而被调用
[self.window makeKeyAndVisible];
通过调用makeKeyAndVisible,它使RootViewController
可见,即使它只在后台任务中处于唤醒状态。要解决此问题,我必须将此行移动到applicationDidBecomeActive
- (void)applicationDidBecomeActive:(UIApplication *)application {
[self.window makeKeyAndVisible];
}
因此,现在仅当应用程序处于前台(用户可见)时才调用RootViewController's
viewDidAppear
。但是,我担心的是,当应用程序在设备内存中(活动或非活动)时,applicationDidBecomeActive
将被调用多次。
- 用户启动应用程序
- 应用程序从跳板重新激活
- 设备解锁
- 结束呼叫
如果我在应用程序生命周期中多次调用UIWindow's
makeKeyAndVisible
,会有什么问题吗?
您可以轻松地确保makeKeyAndVisible
只发生一次:包装它。
if (!self.window.keyWindow) {
[self.window makeKeyAndVisible;
} else if (self.window.hidden) {
self.window.hidden = NO;
}