将分析的字符串列表添加到字典 wpf c#

Question

我正在尝试将话语解析为单词并将这些单词保存在列表中。我想使用话语数字键将每个列表添加到字典中。我想将每个话语与其他话语的相似性进行比较。我试过这个，但没有用。谁能帮帮我！

谢谢

public string[] utterance = new string[4];
    Dictionary<string, List> wording = new Dictionary<string, List>();
    public void splitit()
    {          
     utterance[0] = "Fish attacked Nemo's parents";
     utterance[1] = "Only one fish egg left after fish attacked Nemo's parents and that was Nemo.";
     utterance[2] = "Nemo grow up and went to school.";
     utterance[3] = "Nemo got bored during the lecture and went to ocean with his friends.";
        for (int x=0; x < 4; x++)
        {
            string[] words = utterance[x].Split(' ');
            List<string> Tokens = new List<string>();
            foreach (string word in words)
            {
                Tokens.Add(word);
            }
            //string parsed = Tokens[1];
            //foreach(string tok in Tokens)
            //{
            //   List<string> listing = new List<string>();
            //    listing.Add (tok);
            //    wording.Add("utterance"+x, listing);
            //    //listBox1.Items.Add("utterance"+x+" : "+tok);
            //}
            for (int w = 0; w < 4; w++)
            { 
            wording.Add("utterance"+x,Tokens);
            }
        }
    }
}

我像这样解决了这个问题，它现在可以工作了：

for （int x=0; x <36; x++） {

            string[] words = utterance[x].Split(' ');
            ArrayList Tokens = new ArrayList();

            foreach (string word in words)
            {
                Tokens.Add(word);
            }

            ArrayList listing = new ArrayList();
            foreach (string tok in Tokens)
            {
                listing.Add(tok);
            }
                wording.Add("utterance" + x, listing);
               counting = wording["utterance0"].Count;
      }

Answer 1

只需更改几件事：

像这样声明Disctionary：Dictionary<string, List<string>>，最后，为每个句子添加托肯，就像这样wording.Add(utterance[w],Tokens);

Dictionary<string, List<string>> wording = new Dictionary<string, List<string>>();
public void splitit()
{          
 utterance[0] = "Fish attacked Nemo's parents";
 utterance[1] = "Only one fish egg left after fish attacked Nemo's parents and that was Nemo.";
 utterance[2] = "Nemo grow up and went to school.";
 utterance[3] = "Nemo got bored during the lecture and went to ocean with his friends.";
    for (int x=0; x < 4; x++)
    {
        string[] words = utterance[x].Split(' ');
        List<string> Tokens = new List<string>();
        foreach (string word in words)
        {
            Tokens.Add(word);
        }
        //string parsed = Tokens[1];
        //foreach(string tok in Tokens)
        //{
        //   List<string> listing = new List<string>();
        //    listing.Add (tok);
        //    wording.Add("utterance"+x, listing);
        //    //listBox1.Items.Add("utterance"+x+" : "+tok);
        //}
        for (int w = 0; w < 4; w++)
        { 
        wording.Add(utterance[w],Tokens);
        }
    }
}

}

Answer 2

public string[] utterance = new string[4];
Dictionary<string, List<string>> wording = new Dictionary<string, List<string>>();
public void splitit()
{          
 utterance[0] = "Fish attacked Nemo's parents";
 utterance[1] = "Only one fish egg left after fish attacked Nemo's parents and that was Nemo.";
 utterance[2] = "Nemo grow up and went to school.";
 utterance[3] = "Nemo got bored during the lecture and went to ocean with his friends.";
    for (int x=0; x < 4; x++)
    {
        wording.Add("utterance"+x,utterance[x].Split(' ').ToList());
    }
}