如何在Pandas DataFrame的几列中进行独热编码,以便以后与Scikit-Learn一起使用



假设我有以下数据

import pandas as pd
data = {
    'Reference': [1, 2, 3, 4, 5],
    'Brand': ['Volkswagen', 'Volvo', 'Volvo', 'Audi', 'Volkswagen'],
    'Town': ['Berlin', 'Berlin', 'Stockholm', 'Munich', 'Berlin'],
    'Mileage': [35000, 45000, 121000, 35000, 181000],
    'Year': [2015, 2014, 2012, 2016, 2013]
 }
df = pd.DataFrame(data)

我想对"品牌"和"城镇"两列进行单热编码,以训练分类器(例如使用Scikit-Learn)并预测年份。

训练

分类器后,我将希望预测新传入数据的年份(不在训练中使用),我需要重新应用相同的热编码。例如:

new_data = {
    'Reference': [6, 7],
    'Brand': ['Volvo', 'Audi'],
    'Town': ['Stockholm', 'Munich']
}

在这种情况下,对 Pandas 数据帧上的 2 列进行独热编码的最佳方法是什么,知道需要对多个列进行编码,并且以后需要能够对新数据应用相同的编码。

这是一个后续问题,即如何在SkLearn中重复使用LabelBinarizer进行输入预测

请考虑以下方法。

演示:

from sklearn.preprocessing import LabelBinarizer
from collections import defaultdict
d = defaultdict(LabelBinarizer)
In [7]: cols2bnrz = ['Brand','Town']
In [8]: df[cols2bnrz].apply(lambda x: d[x.name].fit(x))
Out[8]:
Brand    LabelBinarizer(neg_label=0, pos_label=1, spars...
Town     LabelBinarizer(neg_label=0, pos_label=1, spars...
dtype: object
In [10]: new = pd.DataFrame({
    ...:     'Reference': [6, 7],
    ...:     'Brand': ['Volvo', 'Audi'],
    ...:     'Town': ['Stockholm', 'Munich']
    ...: })
In [11]: new
Out[11]:
   Brand  Reference       Town
0  Volvo          6  Stockholm
1   Audi          7     Munich
In [12]: pd.DataFrame(d['Brand'].transform(new['Brand']), columns=d['Brand'].classes_)
Out[12]:
   Audi  Volkswagen  Volvo
0     0           0      1
1     1           0      0
In [13]: pd.DataFrame(d['Town'].transform(new['Town']), columns=d['Town'].classes_)
Out[13]:
   Berlin  Munich  Stockholm
0       0       0          1
1       0       1          0
您可以使用

pandas 提供get_dummies函数并转换分类值。

像这样的东西..

import pandas as pd
data = {
    'Reference': [1, 2, 3, 4, 5],
    'Brand': ['Volkswagen', 'Volvo', 'Volvo', 'Audi', 'Volkswagen'],
    'Town': ['Berlin', 'Berlin', 'Stockholm', 'Munich', 'Berlin'],
    'Mileage': [35000, 45000, 121000, 35000, 181000],
    'Year': [2015, 2014, 2012, 2016, 2013]
 }
df = pd.DataFrame(data)
train = pd.concat([df.get(['Mileage','Reference','Year']),
                           pd.get_dummies(df['Brand'], prefix='Brand'),
                           pd.get_dummies(df['Town'], prefix='Town')],axis=1)

对于测试数据,您可以:

new_data = {
    'Reference': [6, 7],
    'Brand': ['Volvo', 'Audi'],
    'Town': ['Stockholm', 'Munich']
}
test = pd.DataFrame(new_data)
test = pd.concat([test.get(['Reference']),
                           pd.get_dummies(test['Brand'], prefix='Brand'),
                           pd.get_dummies(test['Town'], prefix='Town')],axis=1)
# Get missing columns in the training test
missing_cols = set( train.columns ) - set( test.columns )
# Add a missing column in test set with default value equal to 0
for c in missing_cols:
    test[c] = 0
# Ensure the order of column in the test set is in the same order than in train set
test = test[train.columns]

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