PHP AJAX按钮单击计数器



我想单击按钮计数器。当您单击该按钮时,文本会更改时,单击按钮时,我想写入数据库,但我无法管理。

<button type="button" class="btn btn-info" style="width:90%;" id="textChanger" onclick="counter;"><h4><i class="glyphicon glyphicon-earphone" aria-hidden="true">  </i> XXXX XXX XXX <h6>Show Number</h6></h4></button>
document.getElementById("textChanger").onclick= function(){
        document.getElementById("textChanger").innerHTML="<h4><i class="glyphicon glyphicon-earphone" aria-hidden="true">  </i> <?php echo $nrTelefonAnunt ?> </h4>";
         }

这是我管理文本更改的代码,现在我该怎么写于数据库,我尝试了一些方法,但没有任何方法

感谢大家通过添加此操作的答案:

$('#textChanger').click(function(){
    $.ajax({
        url : 'rate.php?idanunt="<?php echo $idAnunt ?>"', 
        type : 'post',  
        success : function(data){
        }
    });
});

尝试此

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<button type="button" class="btn btn-info" style="width:90%;" id="textChanger" onclick="counter;">1</button>
<script>
document.getElementById("textChanger").onclick= function(){
        var count = document.getElementById("textChanger").innerHTML;
        count = parseInt(count) + 1;
        document.getElementById("textChanger").innerHTML=count;
         }
</script>

尝试此

 <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.1.1/jquery.js"></script>
 <button type="button" class="btn btn-info" style="width:90%;" id="textChanger" onclick="counter;"><h4><i class="glyphicon glyphicon-earphone" aria-hidden="true">  </i> <span>XXXXX</span> <h6>Show Number</h6></h4></button>
<script>
count=0;
 $(document).on("click","button",function(){
     count++;
     $('span').text(count);

  });  
</script>

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