基于Python 3中不同模式的分裂句子

Question

我需要基于一系列正则模式来拆分字符串。我能够单独应用分配，但问题是递归分开的。

例如，我有这个句子：

"I want to be splitted using different patterns. It is a complex task, and not easy to solve; so, I would need help."

我需要基于"，"，"；和"。"。

Resulst应该是5个句子，例如：

"I want to be splitted using different patterns."
"It is a complex task,"
"and not easy to solve;"
"so,"
"I would need help."

到目前为止我的代码：

import re
sample_sentence = "I want to be splitted using different patterns. It is a complex task, and not easy to solve; so, I would need help."
patterns = [re.compile('(?<=.) '),
            re.compile('(?<=,) '),
            re.compile('(?<=;) ')]
for pattern in patterns:
    splitted_sentences = pattern.split(sample_sentence)
    print(f'Pattern used: {pattern}')

如何在不失去结果并获得预期结果的情况下应用不同的模式？

编辑：我需要一个一个一个模式，因为我需要在每个模式的结果中进行一些检查，因此以某种树算法运行它。很抱歉没有完全解释，在我的脑海中很明显，但我认为它不会有副作用。

Answer 1

您可以使用|：

加入每个模式

import re
s = "I want to be splitted using different patterns. It is a complex task, and not easy to solve; so, I would need help."
result = re.split('(?<=.)s|,s*|;s*', s)

输出：

['I want to be splitted using different patterns.', 'It is a complex task', 'and not easy to solve', 'so', 'I would need help.']

Answer 2

python在re

中具有

尝试

re.split('; | , | . ',ourString)

Answer 3

我想不出一个正则是这样做的。因此，您可以做什么，它可以用自定义定义的定义符，例如 $ $ ，然后根据此定界符拆分句子。

new_sent = re.sub('[.,;]', '$DELIMITER$', sent)
new_sent.split('$DELIMITER$')

这将导致以下内容：

['I want to be splitted using different patterns',
 ' It is a complex task',
 ' and not easy to solve',
 ' so',
 ' I would need help',
 '']

注意：上面的输出具有附加的空字符串。这是因为句子结尾处有一段时间。为避免这种情况，您可以从列表中删除该空元素，也可以在句子结尾处替换自定义定义定义的定界符。

。

new_sent = re.sub('[.,;]', '$DELIMITER$', sent)
new_sent = re.sub('$DELIMITER$$', '', new_sent)
new_sent.split('$DELIMITER$')

，如果您有一个分界符列表，则可以使用以下代码使您的正则模式：

delimiter_list = [',', '.', ':', ';']
pattern = '[' + ''.join(delimiter_list) + ']' #will result in [,.:;]
new_sent = re.sub(pattern, '$DELIMITER$', sent)
new_sent = re.sub('$DELIMITER$$', '', new_sent)
new_sent.split('$DELIMITER$')

我希望这会有所帮助！

Answer 4

使用字符类使用lookBehind：

import re
s = "I want to be splitted using different patterns. It is a complex task, and not easy to solve; so, I would need help."
result = re.split('(?<=[.,;])s', s)
print(result)

输出：

['I want to be splitted using different patterns.', 
 'It is a complex task,', 
 'and not easy to solve;',
 'so,', 
 'I would need help.']