| Col1 | Col2 | Col3 | Col4 | Col5
--------------------------------------------------
| B1 | A1 | somedata | data | somedata
| B2 | A1 | somedata | data | somedata
| B3 | A1 | null | data | somedata
| C1 | B1 | null | data | somedata
| C2 | B1 | 1 | data | somedata
| D1 | C1 | 1 | data | somedata
| D2 | C1 | 4 | data | somedata
| D3 | C1 | 4 | data | somedata
| Z1 | K1 | A | B | C
| Z1 | K2 | A | B | C
A1
/
B1 B2 B3
/
C1 C2
/
D1 D2 D3
我有以下表格结构。Col1 拥有 Col2 的孩子。其他列具有其他相关数据。该表包含树状结构的数据。是否可以创建一个查询来提供 A1 的所有子项。在这种情况下,它将是
B1
B2
B3
C1
C2
D1
D2
D3
我只熟悉简单的联接,不知道如何查询数据。任何帮助将不胜感激。
不应该太复杂:
SQL> with test (col1, col2) as
2 (select 'B1', 'A1' from dual union all
3 select 'B2', 'A1' from dual union all
4 select 'B3', 'A1' from dual union all
5 select 'C1', 'B1' from dual union all
6 select 'C2', 'B1' from dual union all
7 select 'D1', 'C1' from dual union all
8 select 'D2', 'C1' from dual union all
9 select 'D3', 'C1' from dual union all
10 select 'Z1', 'K1' from dual union all
11 select 'Z1', 'K2' from dual
12 )
13 select col1
14 from test
15 start with col2 = 'A1'
16 connect by prior col1 = col2
17 order by col1;
CO
--
B1
B2
B3
C1
C2
D1
D2
D3
8 rows selected.
SQL>