从安卓呼叫邮件PHP文件不起作用

Question

我的安卓应用程序中有以下功能：

void sendEmail(String PHPfileUurl, String receiverEmail, String fromEmail) {
ParseUser currentUser = ParseUser.getCurrentUser();
StringBuilder messageBuilder = new StringBuilder();
for (int i=0; i<productsOrdered.size(); i++){
messageBuilder.append(productsOrdered.get(i)).append("n");
}
String mess = messageBuilder.toString();
String parameters = "name=" + currentUser.getString(Configurations.USER_FULLNAME) +
"&fromEmail=" + fromEmail +
"&receiverEmail=" + receiverEmail +
"&messageBody=" + mess +
"&storeName=" + Configurations.MERCHANT_NAME +
"&shippingAddress=" + currentUser.getString(Configurations.USER_SHIPPING_ADDRESS);
String strURL = PHPfileUurl + parameters;
strURL = strURL.replace(" ", "%20");
strURL = strURL.replace("n", "%20");
Log.i(Configurations.TAG, "PHP STRING URL: " + strURL);
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
try {
URL url;
url = new URL(strURL);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setConnectTimeout(20000);
conn.setReadTimeout(20000);
conn.setDoInput(true);
conn.setDoOutput(true);
if( conn.getResponseCode() == HttpURLConnection.HTTP_OK ){
InputStream is = conn.getInputStream();
Log.i(Configurations.TAG, "EMAIL RESPONSE: " + conn.getResponseMessage());
} else {
InputStream err = conn.getErrorStream();
Log.i(Configurations.TAG, "ERROR ON EMAIL: " + err);
}
} catch (IOException e) {e.printStackTrace(); }
}

当我调用该函数时，Logcat 会打印出以下消息：

I/log-: PHP STRING URL: http://example.com/myapp/email-admin.php?name=Mark%20Doe&fromEmail=[e-mail]&receiverEmail=[e-mail]&messageBody=PRODUCT%20ID:%20Q3nQgZdlFG%20---%20PRODUCT:%20Nike%20Sport%20Shoes%20black%20%20---%20QUANTITY:%201%20---%20SIZE:%20L%20&storeName=Z%20Store%20Inc.&shippingAddress=John%20Doe,%20121%20Church%20Avenue,%20ASD123,%20London,%20UK
I/log-: EMAIL RESPONSE: OK

所以我假设一切都很好，因为响应 = 正常。但事实并非如此，因为我不会在 [e-mail] 收到任何电子邮件(还有另一个电子邮件地址，我发布了一个假的作为示例，Logcat 将我的真实电子邮件地址打印为receiverEmail(。

这是我mail.php文件：

// POST Variables
$name = $_POST['name'];
$fromEmail = $_POST['fromEmail'];
$receiverEmail = $_POST['receiverEmail'];
$messageBody = $_POST['messageBody'];
$storeName = $_POST['storeName'];
$shippingAddress = $_POST['shippingAddress'];
$headers = 'From: ' .$fromEmail;
// SUBJECT 
$subject = "New order from " .$name. " on '" .$storeName. "'";

// COMPOSE MESSAGE 
$message = 
"ORDER DETAILS:n".
$messageBody.
"nnName: " .$name. 
"nUser Email: " .$fromEmail.
"nShipping Address: " .$shippingAddress
;
/* Finally send email */
mail($receiverEmail,
$subject, 
$message, 
$headers
);
/* Result */
echo "Email Sent to: " .$receiverEmail. "n Message: " .$message;

我的代码有问题吗？ 有没有其他方法可以从我自己的服务器调用邮件.php文件？我也尝试过这个问题，但我无法在我的项目中导入DefaultHttpClient类。

Answer 1

如果将$_POST 更改为 $_GET 会更容易 但是如果消息内部有 (&something=( 的 $_GET 方法中的问题 它只会收到一半的消息，因为 &something= 会设置为另一个 $_GET，如果消息太长，你可能会遇到一些问题，

因此，如果您想使用 $_POST 方法而不是 $_GET

你需要改变你的Java代码， 确保导入地图，然后将其更改为此

void sendEmail(String PHPfileUurl, String receiverEmail, String fromEmail) {
ParseUser currentUser = ParseUser.getCurrentUser();
StringBuilder messageBuilder = new StringBuilder();
for (int i=0; i<productsOrdered.size(); i++){
messageBuilder.append(productsOrdered.get(i)).append("n");
}
String mess = messageBuilder.toString();

Map<String,Object> params = new LinkedHashMap<>();
params.put("name", currentUser.getString(Configurations.USER_FULLNAME));
params.put("fromEmail", fromEmail);
params.put("receiverEmail", receiverEmail);
params.put("messageBody", mess);
params.put("storeName", Configurations.MERCHANT_NAME);
params.put("shippingAddress", currentUser.getString(Configurations.USER_SHIPPING_ADDRESS);
StringBuilder postData = new StringBuilder();
for (Map.Entry<String,Object> param : params.entrySet()) {
if (postData.length() != 0) postData.append('&');
postData.append(URLEncoder.encode(param.getKey(), "UTF-8"));
postData.append('=');
postData.append(URLEncoder.encode(String.valueOf(param.getValue()), "UTF-8"));
}
byte[] postDataBytes = postData.toString().getBytes("UTF-8");

String strURL = PHPfileUurl;
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
try {
URL url;
url = new URL(strURL);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setConnectTimeout(20000);
conn.setReadTimeout(20000);
conn.setDoInput(true);
conn.setDoOutput(true);
conn.getOutputStream().write(postDataBytes);

if( conn.getResponseCode() == HttpURLConnection.HTTP_OK ){
InputStream is = conn.getInputStream();
Log.i(Configurations.TAG, "EMAIL RESPONSE: " + conn.getResponseMessage());
} else {
InputStream err = conn.getErrorStream();
Log.i(Configurations.TAG, "ERROR ON EMAIL: " + err);
}
} catch (IOException e) {e.printStackTrace(); }
}

Answer 2

使用 $_GET 而不是 $_POST ，

将所有变量从

$name = $_POST['name'];

自

$name = $_GET['name'];